Among the choices, the only one that can be considered a carnivore is C. Adelie penguin. Adelie penguins are found in the Arctic, and feed on aquatic creatures such as krill, fish, and squid. Krill is a type of crustacean that feeds on phytoplankton, which is at the bottom of the food chain.
Answer: It takes 3.120 seconds for the concentration of A to decrease from 0.860 M to 0.260 M.
Explanation:
Integrated rate law for second order kinetics is given by:
k = rate constant = ![0.610M^{-1}s^{-1}](https://tex.z-dn.net/?f=0.610M%5E%7B-1%7Ds%5E%7B-1%7D)
= initial concentration = 0.860 M
a= concentration left after time t = 0.260 M
![t=3.120s](https://tex.z-dn.net/?f=t%3D3.120s)
Thus it takes 3.120 seconds for the concentration of A to decrease from 0.860 M to 0.260 M.
Answer:
is there a way of reducing light pollution at the edges of a forest work?
Answer:
The new volume is 1.62 L
Explanation:
Boyle's law says:
"The volume occupied by a given gas mass at constant temperature is inversely proportional to the pressure." It is expressed mathematically as:
Pressure * Volume = constant
o P * V = k
Charles's law is a law that says that when the amount of gas and pressure are kept constant, the ratio between volume and temperature will always have the same value:
![\frac{V}{T}=k](https://tex.z-dn.net/?f=%5Cfrac%7BV%7D%7BT%7D%3Dk)
Gay-Lussac's law indicates that when there is a constant volume, as the temperature increases, the gas pressure increases. And when the temperature is decreased, the gas pressure decreases. So this law indicates that the quotient between pressure and temperature is constant.
Gay-Lussac's law can be expressed mathematically as follows:
![\frac{P}{T}=k](https://tex.z-dn.net/?f=%5Cfrac%7BP%7D%7BT%7D%3Dk)
Combined law equation is the combination of three gas laws called Boyle's, Charlie's and Gay-Lusac's law.
![\frac{P*V}{T}=k](https://tex.z-dn.net/?f=%5Cfrac%7BP%2AV%7D%7BT%7D%3Dk)
Having an initial state 1 and a final state 2 it is possible to say that:
![\frac{P1*V1}{T1} =\frac{P2*V2}{T2}](https://tex.z-dn.net/?f=%5Cfrac%7BP1%2AV1%7D%7BT1%7D%20%3D%5Cfrac%7BP2%2AV2%7D%7BT2%7D)
Standard temperature and pressure (STP) indicate pressure conditions P = 1 atm and temperature T = 0 ° C = 273 ° K. Then:
- P1= 1 atm
- V1= 1.2 L
- T1= 273 °K
- P2= 0.80 atm
- V2= ?
- T2= 21°C= 294 °K
Replacing:
![\frac{1 atm* 1.2 L}{273K} =\frac{0.8 atm*V2}{294K}](https://tex.z-dn.net/?f=%5Cfrac%7B1%20atm%2A%201.2%20L%7D%7B273K%7D%20%3D%5Cfrac%7B0.8%20atm%2AV2%7D%7B294K%7D)
Solving:
![V2=\frac{1 atm*1.2 L}{273 K} *\frac{294 K}{0.8 atm}](https://tex.z-dn.net/?f=V2%3D%5Cfrac%7B1%20atm%2A1.2%20L%7D%7B273%20K%7D%20%2A%5Cfrac%7B294%20K%7D%7B0.8%20atm%7D)
V2= 1.62 L
<u><em>The new volume is 1.62 L</em></u>
<u><em></em></u>