Stage 2 sleep shows Theta waves
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B It’s a physical change because the water and the salt kept their original properties.</span>
Answer:(a)does not change
Explanation:
Given
Submarine is 50 m below the surface
Now submarine descends to 100 m and stops
As we know that pressure difference at a depth of h is given by
where =Density of fluid
g=acceleration due to gravity
h=height below free surface of liquid
buoyant force is equal to volume displaced by object
as the submarine is already in water therefore buoyant force will remain same.
Answer: 909 m/s
Explanation:
Given
Mass of the bullet, m1 = 0.05 kg
Mass of the wooden block, m2 = 5 kg
Final velocities of the block and bullet, v = 9 m/s
Initial velocity of the bullet v1 = ? m/s
From the question, we would notice that there is just an object (i.e the bullet) moving before the collision. Also, even after the collision between the bullet and wood, the bullet and the wood would move as one object. Thus, we would use the conservation of momentum to solve
m1v1 = (m1 + m2) v, on substituting, we have
0.05 * v1 = (0.05 + 5) * 9
0.05 * v1 = 5.05 * 9
0.05 * v1 = 45.45
v1 = 45.45 / 0.05
v1 = 909 m/s
Thus, the original velocity of the bullet was 909 m/s