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dybincka [34]
3 years ago
6

Please help on this one? The mass on the spring in this diagram is in harmonic motion between x = -5cm and x=5cm

Physics
1 answer:
shutvik [7]3 years ago
8 0

c ... max speed zero accel

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A 2800 kg truck moving at 12 m/s to the right hits a stopped 1100 kg car. What is the combined velocity the moment they stick to
leva [86]

Answer:

The combined velocity is 8.61 m/s.

Explanation:

Given that,

The mass of a truck, m = 2800 kg

Initial speed of truck, u = 12 m/s

The mass of a car, m' = 1100 kg

Initial speed of the car, u' = 0

We need to find the combined velocity the moment they stick together. Let it is V. Using the conservation of momentum.

m_1v_1+m_2v_2=(m_1+m_2)V\\\\V=\dfrac{m_1v_1+m_2v_2}{(m_1+m_2)}\\\\V=\dfrac{2800\times 12+0}{2800+1100}\\\\V=8.61\ m/s

So, the combined velocity is 8.61 m/s.

5 0
3 years ago
Which will be attracted to (or repelled by) a magnet ?
Dima020 [189]
I believe it’s A C F
4 0
3 years ago
Read 2 more answers
One long wire lies along an x axis and carries a current of 43 A in the positive x direction. A second long wire is perpendicula
qwelly [4]

Answer:

Bnet=1.006*10^-6T

Explanation:

One long wire lies along an x axis and carries a current of 43 A in the positive x direction. A second long wire is perpendicular to the xy plane, passes through the point (0, 5.9 m, 0), and carries a current of 41 A in the positive z direction. What is the magnitude of the resulting magnetic field at the point (0, 1.7 m, 0)?

the magnetic field Bnet=\sqrt{b1^2+b2^2}

the magnetic field due this long wire is given by

B1=∨I1/(2\pi *R1)..............................1

B2=∨I2/(2\pi *R2)............................2

Bnet=\sqrt{(vI1/2*pi*R1)^2+(vI2/2*pi*R2)^2}.......................3

Bnet=v/2*pi\sqrt{(I1/R1)^2+(i2/R2)^2}

Bnet=4*pi*10^-7/(2\pi)\sqrt{(43/1.7)^2+(41/29.5)^2}

Bnet=0.0000002*(641.72)^.5

Bnet=1.006*10^-6T

8 0
4 years ago
Explain the range of effectiveness of each fundamental force by describing the distance that each force influence nearby matter
Bas_tet [7]

Answer:

Actually, gravity is the weakest of the four fundamental forces. Ordered from strongest to weakest, the forces are 1) the strong nuclear force, 2) the electromagnetic force, 3) the weak nuclear force, and 4) gravity.

6 0
3 years ago
The temperature of a smelting furnace is found to be 2000 ℃. Find the
IRISSAK [1]

Answer:

a) The equivalent temperature of 2000 ºC is 3632 ºF.

b) The equivalent temperature of 2000 ºC is 4091.67 R.

c) The equivalent temperature of 2000 ºC is 2273.15 K.

d) The equivalent temperature of 2000 ºC is 1600 ºRe.

Explanation:

a) The equivalent temperature on the Fahrenheit scale is defined by the following formula:

T_{F} = \frac{9}{5}\cdot T_{C}+32 (Eq. 1)

Where:

T_{C} - Temperature, measured in degrees Celsius.

T_{F} - Temperature, measured in degrees Fahrenheit.

If we know that T_{C} = 2000\,^{\circ}C, then the temperature is:

T_{F} = \frac{9}{5}\cdot (2000\,^{\circ}C)+32\,^{\circ}F

T_{F} = 3632\,^{\circ}F

The equivalent temperature of 2000 ºC is 3632 ºF.

b) From result in a) we determine the equivalent temperature on the Rankine scale by using the following formula:

T_{R} = T_{F}+459.67 (Eq. 2)

Where:

T_{F} - Temperature, measured in degrees Fahrenheit.

T_{R} - Temperature, measured in Rankine.

If we know that T_{F} = 3632\,^{\circ}F, then the temperature is:

T_{R} = 3632\,^{\circ}F+459.67\,R

T_{R} = 4091.67\,R

The equivalent temperature of 2000 ºC is 4091.67 R.

c) The equivalent temperature on the absolute scale is calculated by using this expression:

T_{K} = T_{C}+273.15 (Eq. 3)

Where:

T_{C} - Temperature, measured in degrees Celsius.

T_{K} - Temperature, measured in Kelvin.

If we know that T_{C} = 2000\,^{\circ}C, then the temperature is:

T_{K} = 2000\,^{\circ}C+273.15\,K

T_{K} = 2273.15\,K

The equivalent temperature of 2000 ºC is 2273.15 K.

d) The equivalent temperature on the Réaumur scale is calculated by applying this expression:

T_{Re} = \frac{4}{5}\cdot T_{C} (Eq. 4)

Where:

T_{C} - Temperature, measured in degrees Celsius.

T_{Re} - Temperature, measured in degrees Réaumur.

If we know that T_{C} = 2000\,^{\circ}C, then the temperature is:

T_{Re} = \frac{4}{5}\cdot (2000\,^{\circ}C)

T_{Re} = 1600\,^{\circ}Re

The equivalent temperature of 2000 ºC is 1600 ºRe.

5 0
3 years ago
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