The coefficient of kinetic friction on the horizontal surface, μ = 0.39.
The work done on the package by friction as it slides down the circular arc from A to B, W = -4.176.
<h3>What is the frictional force acting on the package moving on the track?</h3>
Frictional force is the force which opposes the motion of an object over another.
Frictional force acts at the surface of contact of the objects.
The frictional force, F is related to the coefficient of kinetic friction on the horizontal surface, μ, and the normal reaction or weight, mg, of the package as follows:
F = μmg
Work done against friction, W = F * d
W = μmgd
The Kinetic energy of the package is equal to the work done against friction.
Kinetic energy of the package = mv²/2
μmgd = mv²/2
μ = v²/2gd
μ = 4.8²/(2 * 9.81 * 3)
μ = 0.39
b. Work done on the package by friction as it slides down the circular arc from A to B is given as follows:
W = mv²/2 - mgh
W = v²/2 - gh
W = 4.8²/2 - 9.81 * 1.6
W = -4.176
In conclusion, the work done by friction is lost in the form of heat.
Learn more about coefficient of kinetic friction at: brainly.com/question/20241845
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