Step-by-step explanation:
since in a triangle each side must be shorter than the sum of the other 2 sides (otherwise the end points cannot connect, and there is no triangle), the necessary inequality condition must be
side < 1 + 2 = 3
so,
side < 3
for a lower limit let's go through the cases
1 < 2 + side (is always true)
2 < 1 + side
1 < side (side must be larger than 1)
and again
side < 1 + 2 = 3
side < 3
so the full restriction for the third side is
1 < side < 3
En matemáticas, un conjunto contable es un conjunto con la misma cardinalidad (número de elementos) que un subconjunto del conjunto de números naturales. Un conjunto contable es un conjunto finito o un conjunto contable infinito.
Answer:
<h2><em><u>120</u></em><em><u> </u></em><em><u>square</u></em><em><u> </u></em><em><u>units</u></em><em><u> </u></em></h2>
Step-by-step explanation:
<em><u>Given</u></em><em><u>, </u></em>
Base of the parallelogram = 10
Height of the parallelogram = 12
<em><u>Therefore</u></em><em><u>, </u></em>
Area of the parallelogram = <em>base</em><em> </em><em>×</em><em> </em><em>height</em><em> </em>
= 10 × 12
= 120
<em><u>Hence</u></em><em><u>,</u></em>
<em><u>Area</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>parallelogram</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>120</u></em><em><u> </u></em><em><u>square</u></em><em><u> </u></em><em><u>units</u></em><em><u> </u></em><em><u>(</u></em><em><u>Ans</u></em><em><u>)</u></em>
7 goes into 9, that's 1.
Remaining 2.
Move the 2 close to 3, you have 23.
7 into the 23, that's 3 times. 3 times 7 is 21.
So you are left with 2.
The answer is 13 remainder 2.
13\2\7
Combine like terms.
4. 5x+9y+3x-2y
8x+7y
7. 22u-6u+4t+4t-8u
8u+8t
10. 23m+4n-3m
20m+4n
