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raketka [301]
3 years ago
11

In a diagnostic test for leukemia, a person receives 4.1 mL of a solution containing selenium-75. If the activity of the seleniu

m-75 is 45 μCi/mL , what dose, in microcuries, does the patient receive?
Chemistry
2 answers:
Tcecarenko [31]3 years ago
8 0

To solve this problem, we can simply calculate for the dose by multiplying the volume of solution containing Selenium 75 and the activity of the Selenium 75. That is:

dose = 4.1 mL * (45 μCi/mL)

dose = 184.5 μCi

faust18 [17]3 years ago
4 0

Answer: Patient received 184.5\mu Ci of dose.

Explanation:

Volume of solution received by the patient = 4.1 mL

Activity of selenium-75 = 45\mu Ci/mL

In one mL of solution there are 45 \mu Ci of selenium -75 dose,

In 4.1 ml  solution will contain=45\mu Ci/mL\times 4.1 ml=184.5\mu Ci

The patient received the dose of 184.5\mu Ci of selenium-75 in 4.1 mL solution.

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See explanation below

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