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raketka [301]
3 years ago
11

In a diagnostic test for leukemia, a person receives 4.1 mL of a solution containing selenium-75. If the activity of the seleniu

m-75 is 45 μCi/mL , what dose, in microcuries, does the patient receive?
Chemistry
2 answers:
Tcecarenko [31]3 years ago
8 0

To solve this problem, we can simply calculate for the dose by multiplying the volume of solution containing Selenium 75 and the activity of the Selenium 75. That is:

dose = 4.1 mL * (45 μCi/mL)

dose = 184.5 μCi

faust18 [17]3 years ago
4 0

Answer: Patient received 184.5\mu Ci of dose.

Explanation:

Volume of solution received by the patient = 4.1 mL

Activity of selenium-75 = 45\mu Ci/mL

In one mL of solution there are 45 \mu Ci of selenium -75 dose,

In 4.1 ml  solution will contain=45\mu Ci/mL\times 4.1 ml=184.5\mu Ci

The patient received the dose of 184.5\mu Ci of selenium-75 in 4.1 mL solution.

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A 265-mL flask contains pure helium at a pressure of 751 torrs. A second flask with a volume of 465 mL contains pure argon at a
Nadya [2.5K]

Answer:

Total Pressure = 745.6 torr

Partial Pressure of He = 272.8 torr

Partial Pressure of Ar =  472.8 torr

Explanation:

Step 1: Data given

Volume of the flask helium = 265 mL

Pressure in the helium flask = 751 torr = 751/760 atm

Volume of the flask argon = 465 mL

Pressure in the argon flask = 727 torr = 727/760 atm

The total pressure exerted by a gaseous mixture is equal to the sum of the partial pressures of each individual component in a gas mixture.

Step 2: Calculate total volume

Total volume = 265 mL + 465 mL = 730 mL =  0.730 L

Step 3: Boyle's Law:

P1V1=P2V2

⇒ with P1 = total pressure gas exerts in its own flask

 ⇒ with V1 = volume of flask with stopcock valve closed

 ⇒ with P2 = partial pressure of gas exerts on total volume of both flasks when stopcock valve is opened  

 ⇒ with V2 = total volume of both flasks with stopcock valve opened

Helium using Boyle's Law equation from above:

P1V1=P2V2

⇒ with P1 = Pressure of helium = 751 /760 = 0.98816 atm

 ⇒ with V1 = volume of helium = 0.265 L

 ⇒ with P2 = The new partial pressure of helium

 ⇒ with V2 = total volume = 0.730 L

(0.98816 atm)(0.265L)=P2(0.730L)

P2=0.359 atm

Argon using Boyle's Law equation from above:

P1V1=P2V2

⇒ with P1 = Pressure of argon = 727/760 = 0.95658 atm

 ⇒ with V1 = volume of argon = 0.465 L

 ⇒ with P2 = The new partial pressure of argon

 ⇒ with V2 = total volume = 0.730 L

(0.95658 atm)(0.465L)=P2(0.730L)

P2=0.609 atm

Step 4: Convert pressure in atm to torr

Pressure helium = 0.359 atm = 272.8 torr

Pressure argon = 0.609 atm = 472.8 torr

Step 5: Calculate Total pressure

Ptotal = P(He)+P(Ar)

⇒ Pt  = total pressure of the gas mixture

⇒ P(He) = partial pressure of Helium

 ⇒ P(Ar)  = partial pressure of Argon

Pt = 272.8 torr + 472.8 torr

Pt = 745.6 torr

Total Pressure = 745.6 torr

Partial Pressure of He = 272.8 torr

Partial Pressure of Ar =  472.8 torr

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4 years ago
Which unit can be used to express the rate of a reaction?
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3 years ago
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Crushing large chunks of sodium chloride:<br> What lab equipment
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Goggles Gloves materials
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Given the following balanced reaction of carbonic acid decomposing to produce water and carbon dioxide gas, how many moles of ca
salantis [7]

7.00 mol is the answer

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What is the pOH value of 0.0000877 M HCL
ki77a [65]

Answer:

pOH=9.9

Explanation:

pH=-log[H+]= -log[0.0000877]

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pOH+ pH=14

pOH=14-4.06= 9.91

7 0
3 years ago
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