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dangina [55]
3 years ago
5

NEED ASAP PLEASE !!

Physics
2 answers:
Ilia_Sergeevich [38]3 years ago
8 0

Answer: The correct answer is option (A).

Explanation:

Initial velocity of the balloon = 0 m/s

let the distance covered by the balloon from roof to the ground= h

Time taken by the balloon to reach the ground = t = 2.5 seconds

Acceleration due to  gravity = g =9.8 m/s^2

Using confuse equation of the motion:

h=ut+\frac{1}{2}gt^2

h=0 m/s\times 2.5 s+\frac{1}{2}\times9.8 m/s^2\times (2.5 s)^2=30.625 m\approx 30.6 m

Hence, the correct answer is option (A).

Svetllana [295]3 years ago
3 0
The balloon was 30.65 meters above ground.

ANSWER: A
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3 0
3 years ago
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the positive particle has a charge of 31.7 mC and the particles are 2.80 mm apart, what is the electric field at point A located
vichka [17]

Answer:

the electric field at point A is

E = 5.5 ×10¹³N/C(-x direction)

Explanation:

given

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distance r = 2.80mm

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attached is the diagram of the solution, describing the position of the charge

note x = r/2, where x is the distance from midpoint of r to the particle

using Pythagoras theorem as in the attachment, x = 2.44mm= 2.44×10⁻³m

the electric field at point A is given as

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where k is the electrostatics constant = 1/4πε₀

where ε₀ is permittivity of free space

therefore using E =2{kq/x²}cosθ

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cosθ=1.40/2.44

E =2 {(9.0×10⁹ × 31.7×10⁻³) ÷ (2.44×10⁻³)²}×(1.40/2.44)(-x)

E=2{4.79×10¹³}×(0.574)(-x)

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Vector <em>E= </em>5.5 ×10¹³N/C(-x direction)

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3 years ago
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