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dangina [55]
3 years ago
5

NEED ASAP PLEASE !!

Physics
2 answers:
Ilia_Sergeevich [38]3 years ago
8 0

Answer: The correct answer is option (A).

Explanation:

Initial velocity of the balloon = 0 m/s

let the distance covered by the balloon from roof to the ground= h

Time taken by the balloon to reach the ground = t = 2.5 seconds

Acceleration due to  gravity = g =9.8 m/s^2

Using confuse equation of the motion:

h=ut+\frac{1}{2}gt^2

h=0 m/s\times 2.5 s+\frac{1}{2}\times9.8 m/s^2\times (2.5 s)^2=30.625 m\approx 30.6 m

Hence, the correct answer is option (A).

Svetllana [295]3 years ago
3 0
The balloon was 30.65 meters above ground.

ANSWER: A
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1 year ago
When a 5.0 kg box is hung from a spring, the spring stretches to 50 mm beyond its relaxed length. (a) In an elevator acceleratin
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Answer:

a) the spring will stretch 60.19 mm with the same box attached as it accelerates upwards

b) spring will be relaxed when the elevator accelerates downwards at 9.81 m/s²

Explanation:

Given that;

Gravitational acceleration g = 9.81 m/s²

Mass m = 5 kg

Extension of the spring X = 50 mm = 0.05 m

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a)

Given that; Acceleration of the elevator a = 2 m/s² upwards

Extension of the spring in this situation = X1

Force exerted by the spring = F

we know that;

ma = F - mg

ma = kX1 - mg

we substitute

5 × 2 = 981 × X1 - (5 ×9.81 )

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X1 = 60.19 mm

Therefore the spring  will stretch 60.19 mm with the same box attached as it accelerates upwards

B)

Acceleration of the elevator = a

The spring is relaxed i.e, it is not exerting any force on the box.

Only the weight force of the box is exerted on the box.

ma = mg

a = g

a = 9.81 m/s² downwards.

Therefore spring will be relaxed when the elevator accelerates downwards at 9.81 m/s²

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By these laws, the comet A will have lower orbital speed.

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3 years ago
An object that has a mass of 36.0kg is pushed along a horizontal surface with a force of 85.0N. IF
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0.36m/s^2

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Answer:

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3 years ago
Read 2 more answers
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