All categories

3 years ago

NEED ASAP PLEASE !!

Physics

2 answers:

Ilia_Sergeevich [38]3 years ago

8 0

Answer: The correct answer is option (A).

Explanation:

Initial velocity of the balloon = 0 m/s

let the distance covered by the balloon from roof to the ground= h

Time taken by the balloon to reach the ground = t = 2.5 seconds

Acceleration due to gravity = g =9.8 $m/s^2$

Using confuse equation of the motion:

$h=ut+\frac{1}{2}gt^2$

$h=0 m/s\times 2.5 s+\frac{1}{2}\times9.8 m/s^2\times (2.5 s)^2=30.625 m\approx 30.6 m$

Hence, the correct answer is option (A).

Svetllana [295]3 years ago

3 0

The balloon was 30.65 meters above ground.

ANSWER: A

You might be interested in

A 2.40 kg object on a frictionless horizontal track is attached to the end of a horizontal spring whose force constant is 5.00 N

klemol [59]

Answer: Hello! Here your answer......

Force = 10.244 Newtons

b) No of oscillations = 0.88

Explanation:

Since the block executes SHM we can write it's position as function of time as

ω is the natural frequency of the system

A is the amplitude of the system

Thus accleration of the block

Thus using the given values at t= 3.50 sec we can calculate the acceleration as

thus force can be calculated using newtons second law as

Now no of oscillations can be obtained as

no of oscillations in 3.50 seconds = 3.50/3.976 = 0.88

Hope this helps! (Brainly)♥

3 0

3 years ago

Suppose an asteroid orbiting the sun had an orbital period of 7. 5 years. What would its orbital radius be?.

creativ13 [48]

By using the orbital period equation we will find that the orbital radius is r = 4.29*10^11 m

<h3>What is the orbital period?</h3>

This would be the time that a given body does a complete revolution in its orbit.

It can be written as:

$T = \sqrt{\frac{4*\pi ^2*r^3}{G*M} }$

Where:

π = 3.14
G is the gravitational constant = 6.67*10^(-11) m^3/(kg*s^2)
M is the mass of the sun = 1.989*10^30 kg
r is the radius, which we want to find.

Rewriting the equation for the radius we get:

$T = \sqrt{\frac{4*\pi ^2*r^3}{G*M} }\\\\r = \sqrt[3]{ \frac{T^2*G*M}{4*\pi ^2} }$

Where T = 7.5 years = 7.5*(3.154*10^7 s) = 2.3655*10^8 s

Replacing the values in the equation we get:

$r = \sqrt[3]{ \frac{(2.3655*10^8 s)^2*(6.67*10^{-11} m^3/(kg*s^2))*(1.989*10^{30} kg)}{4*3.14 ^2} } = 4.29*10^{11 }m$

So the orbital radius is 4.29*10^11 m

If you want to learn more about orbits, you can read:

brainly.com/question/11996385

7 0

2 years ago

Simlarity between longitudanal and transverse waves

babymother [125]

For transverse waves, the waves move in perpendicular direction to the source of vibration. For longitudinal waves, the waves move in parallel direction to the source of vibration . They are similar in the sense that energy is transferred in the form of waves.

8 0

3 years ago

Calculate specific heat of liquid if a 450. g iron block is heated to 98.0 C and then droped into a calorimeter with 125 g of un

Naya [18.7K]

Answer:

Specific heat of liquid $1.258 \ J/g^0C.$