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3 years ago

8

Isobutyl alcohol has a boiling point of 108.

1 answer:

Anettt [7]3 years ago

3 0

You can determine the molar of an unknown solute from the boiling point elevation. When you do an experiment, add a certain known amount of the unknown compound to a solvent, say water. Then, determine the boiling point of the solution. The working equations would be the following:

Temp difference = Boiling pt of solution - Boiling point of pure solvent
Moles solute = (Temp difference)(Mass of solvent)/(Ebullioscopic constant of water)
Molar Mass = Mass of solute/Moles solute

The boiling point of water is 100°C,while the ebullioscopic constant is 0.512 °C/molal.

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Bromine pentachloride formula

nekit [7.7K]

Answer:

Bromine pentafluoride, BrF5

bromine pentafluoride is an interhalogen compound and a fluoride of bromine. It is a strong fluorination reagent. BrF5 finds use in oxygen isotope analysis.

4 0

3 years ago

A bottle of wine contains 12.8% ethanol by volume. The density of ethanol (CH3OH) is 0.789 g/cm. Calculate the concentratic etha

Scrat [10]

Answer : The mass percent of ethanol is, 10.38 % and the molality of ethanol is, 2.52 mole/kg

Explanation :

In wine, the solute and solvent are ethanol and water respectively.

Given :

12.8 % ethanol by volume means 12.8 mL ethanol present in 100 mL solution.

Volume of ethanol = 12.8 mL

Volume of solution = 100 mL

Volume of water = 100 - 12.8 = 87.2 mL

Density of ethanol = $0.789g/cm^3=0.789g/mL$

Density of water = 1 g/mL

Now we have to calculate the mass of ethanol and water.

$\text{Mass of ethanol}=\text{Density of ethanol}\times \text{Volume of ethanol}=0.789g/mL\times 12.8mL=10.1g$

and,

$\text{Mass of water}=\text{Density of water}\times \text{Volume of water}=1g/mL\times 87.2mL=87.2g$

Now we have to calculate the total mass of 100 mL of wine.

Total mass of 100 mL of wine = 10.1 + 87.2 = 97.3 g

Now we have to calculate the mass percent of ethanol.

$\text{Mass of percent of ethanol}=\frac{\text{Mass of ethanol}}{\text{Total mass of solution}}\times 100$

$\text{Mass of percent of ethanol}=\frac{10.1g}{97.3g}\times 100=10.38\%$

The mass percent of ethanol is, 10.38 %

Now we have to calculate the molality.

$Molality=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Mass of solvent}}$

Molar mass of ethanol = 46 g/mole

$Molality=\frac{10.1g\times 1000}{46g/mole\times 87.2g}=2.52mole/kg$

The molality of ethanol is, 2.52 mole/kg

6 0

3 years ago

What type of reaction is Mg + 2Ag -> mg2 + 2Ag

bulgar [2K]

Answer:

double replacement ...i think ^^

i hopefully its right

4 0

2 years ago

HELP ME PLEASE I BEG YOU

babunello [35]

True I think is the answer

3 0

3 years ago

A sample of an ideal gas at 1.00 atm and a volume of 1.32 L was placed in a weighted balloon and dropped into the ocean. As the

Amiraneli [1.4K]

Answer:

When the pressure increases to 90.0 atm , the volume of the sample is 0.01467L

Explanation:

To answer the question, we note that

P₁ = 1.00 atm

V₁ = 1.32 L

P₂ = 90 atm.

According to Boyle's law, at constant temperature, the volume of gas is inversely proportional to its pressure

That is P₁V₁ = P₂V₂

Solving the above equation for V₂ we have

$V_2 = \frac{P_1P_2}{P_2}$ that is V₂ = $\frac{1atm*1.32L}{90atm}$ = $\frac{11}{750}L$ or 0.01467L

5 0

3 years ago

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