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kramer
3 years ago
8

Isobutyl alcohol has a boiling point of 108.

Chemistry
1 answer:
Anettt [7]3 years ago
3 0
You can determine the molar of an unknown solute from the boiling point elevation. When you do an experiment, add a certain known amount of the unknown compound to a solvent, say water. Then, determine the boiling point of the solution. The working equations would be the following:

Temp difference = Boiling pt of solution - Boiling point of pure solvent
Moles solute = (Temp difference)(Mass of solvent)/(Ebullioscopic constant of water)
Molar Mass = Mass of solute/Moles solute

The boiling point of water is 100°C,while the ebullioscopic constant is 0.512 °C/molal.
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Tanya [424]

Answer: 0.25M

Explanation: Because of the highest concentration of water and, if they are all the same volume, the greatest amount of water assuming it is a solid solute in a water solution.

5 0
3 years ago
What causes different colors to appear in the sky?
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Answer:

the scattering and reflection of light by dust particles

7 0
4 years ago
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Use the information provided below to answer the
bixtya [17]

Answer:

208 g/mol and 87 g/mol

Explanation:

Number of protons = 82

Atomic mass = 126 + 82 = 208 g/mol

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7 0
3 years ago
What are the properties of CuF2?
ch4aika [34]
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Hope I helped
7 0
3 years ago
Consider a galvanic cell based on the reaction Al^3+_(aq) + Mg_(s) rightarrow Al_(s) + Mg^2+ _(aq) The half-reactions are Al^3+
grin007 [14]

<u>Answer:</u> The standard cell potential of the cell is -0.71 V

<u>Explanation:</u>

The half reactions follows:

<u>Oxidation half reaction:</u>  Mg\rightarrow Mg^{2+}+2e^-;E^o_{Mg^{2+}/Mg}=-2.37V  ( × 3)

<u>Reduction half reaction:</u>  Al^{3+}(aq.)+3e^-\rightarrow Al(s);E^o_{Al^{3+}/Al}=-1.66V  ( × 2)

The balanced cell reaction follows:

2Al^{3+}(aq.)+3Mg(s)\rightarrow 2Al(s)+3Mg^{2+}(aq.)

To calculate the E^o_{cell} of the reaction, we use the equation:

E^o_{cell}=E^o_{cathode}-E^o_{anode}

Substance getting oxidized always act as anode and the one getting reduced always act as cathode.

Putting values in above equation, we get:

E^o_{cell}=-2.37-(-1.66)=-0.71V

Hence, the standard cell potential of the cell is -0.71 V

8 0
3 years ago
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