Bromine has one more electron shell than the chlorine atom making the radius larger than the chlorine atom.
Here we have to draw the mechanism of the reduction reaction between benzaldehyde and sodium borodeuteride to form the corresponding alcohol.
The reducing agent sodium borodeuteride can reduce the aldehydes to its corresponding alcohol. The reaction mechanism is shown in the attached image.
The reaction mechanism can be explained as-
The sodium borodeuteride is highly ionic in nature thus it remains as Na⁺ and BD₄⁻ The deuterium atom of BD₄⁻ attack the carbonyl carbon atom and substitute one of its deuterium as shown in the figure.
One molecule of sodium borodeuteride can reduce four molecules of benzaldehyde. The polar solvent like alcohol donates the proton as shown in the mechanism.
The converted alcohol contains the deuterium atom at the -C center. Thus benzaldehyde is converted to deuteroted benzyl alcohol.
I believe the answer would be diatomic molecule.
Rubidium's atomic number is 37.
Hope this helps!
Answer:
Fe2O3 - S
PbO2 - D
PbO - I
Fe2O - U
Fe(OH)3 - H
FeO2 - T
FeO - R
Pb2O - G
Pb(OH)2 - O
FeOH - N
Pb(OH)3 - A
Explanation:
In writing the formula of ionic compounds we consider the valency or oxidation state of each ion.
For instance, given the compound iron II oxide. The oxidation states of both iron and oxygen are +2 and -2 respectively. Ignoring the charges, this cancels out and we have FeO as the correct formula of the compound.
For Iron III oxide, the oxidation states of iron and oxygen are +3 and -2 respectively, the both atoms exchange charges. If we ignore the signs and write the exchanged numbers as subscripts we obtain the formula Fe2O3.