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shusha [124]
4 years ago
5

Convert the density 2.32 g/mL to the unit kg/m3.

Chemistry
1 answer:
Annette [7]4 years ago
8 0
(2.32g/cm³) x (1kg/1000g)x(1 000 000 cm³/1m³) = 2320 kg/m³


1 ml= 1 cm³
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A beaker contains 249 mL of a 6.54 M HCl(aq) solution. Determine the new concentration of the solution after it is diluted by ad
drek231 [11]

Answer:

The new molarity is 0.614 M

Explanation:

Formula for dilutions is:

M concentrated . Volume of conc = Volume of dil . M diluted

6.54 M . 249 mL = 416 mL . M diluted

Notice that volume of diluted is = Initial volume + What we added of water

(249mL + 167 mL)

(6.54 M . 249 mL) / 416mL = M diluted → 0.614 M

5 0
3 years ago
Select the words that correctly fill in the blanks for this statement:
Lera25 [3.4K]

The correct answer is option A. Three, dumbbell.

The p sublevel has __three_orbitals that are _dunmbbell_-shaped.

The three orbitals of the p sublevel are oriented in three directions along the x, y and Z axis. The orbitals are called px, py and pz. Each p orbital can have a maximum of 2 electrons. Since there are three p orbitals, the p sublevel can have a maximum of 6 electrons.

8 0
4 years ago
Read 2 more answers
Calculate the analytical and equilibrium molar concentrations of the solute species in an aqueous solution containing 155 mg of
Cloud [144]

Answer:

The analytical molar concentration is 0,04743M

The equilibrium concentrations are HA = 0,01281M; H⁺ and A⁻ = 0,03462M

Explanation:

The analytical molar concentrations is:

155mg ≡ 0,155g÷163,4g/mol = 9,486x10⁻⁴ moles

9,486x10⁻⁴ moles ÷ 0,020L = <em>0,04743 M</em>

The trichloroacetic acid [HA] dissociates in water in a 73%, thus:

HA ⇄ H⁺ + A⁻

The equilibrium concentrations are:

HA = 0,04743M ×(100-73)% = 0,01281M

H⁺ and A⁻ = 0,04743M ×73% = 0,03462M

I hope it helps!

8 0
4 years ago
What is the BEST conclusion that can be drawn? I. All the energy contained within the organisms in the web comes from the sun. I
Aleonysh [2.5K]
Therefore, the energy from the sun has been transferred and converted to the last animal on the food chain from the primary producer.
8 0
3 years ago
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Compared to 3.011 × 10²³ atoms of Na, 1.0 mole of Carbon
viva [34]

1. B. has twice as many atoms

2. D. has the same number of molecules

<h3>Further explanation  </h3>

The mole is the number of particles(molecules, atoms, ions) contained in a substance  

1 mol = 6.02.10²³ particles

Can be formulated

N=n x No

N = number of particles

n = mol

No = Avogadro's = 6.02.10²³

1.

3.011 × 10²³ atoms of Na, 1.0 mole of Carbon

1 mole Carbon =  6.02.10²³ atoms, so 1 mole of Carbon B. has twice as many atoms of Na

2.

1.0 mole of H₂S (molar mass 334 g/mol), 1.0 mole of NH₃ (molar mass 17g/mol)

Both have the same number of moles, so they have the same number of molecules

1.0 mole of NH₃ D. has the same number of molecules as  1.0 mole of H₂S

6 0
3 years ago
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