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kenny6666 [7]
3 years ago
9

If you increase the temperature of a reaction, then the reaction rate will ...

Chemistry
1 answer:
DIA [1.3K]3 years ago
6 0
The answer is B.Increase
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How many moles are in 1.52908x1024 molecules of Potassium phosphate (K3(PO4))?
lara31 [8.8K]

Answer:

<h2>2.54 moles</h2>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

n =  \frac{N}{L} \\

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

n =  \frac{1.52908 \times  {10}^{24} }{6.02 \times  {10}^{23} }  \\

We have the final answer as

<h3>2.54 moles</h3>

Hope this helps you

4 0
2 years ago
A farm is located on the edge of a river. The farmer has an insect problem and doubles the amount of pesticides used for several
lora16 [44]
Pollution would go in the form of surface runoff and into rivers and ocean and then disrupt ecosystems because some ecosystems depend on water
7 0
3 years ago
Read 2 more answers
You carry out a titration of a pure weak triprotic acid and only see two major pH jumps. One at 10.0 mL and the second one at 15
mafiozo [28]
23 would be most likely
3 0
3 years ago
9. During an experiment the students prepared three mixtures A)Starch in water B) Sodium chloride solution C) Tincture of Iodine
il63 [147K]

Answer:

See explanation

Explanation:

Tyndall effect refers to the scattering of light in a solution. Tyndall effect occurs when the size of particles in the solution exceeds 1 nm in diameter. Such solutions are actually called false solutions.

In tincture of iodine, the size of particles in solution is less than 1 nm in diameter hence the solution does not exhibit Tyndall effect. Hence, tincture of iodine is a true solution.

Therefore, if the size of particles in solution exceeded 1nm in diameter, Tyndall effect is observed.

7 0
3 years ago
Calculate the percent ionization of nitrous acid in a solution that is 0.311 M in nitrous acid (HNO2) and 0.189 M in potassium n
Alla [95]
<span>HNO2 =====> H+ + NO2-
</span>I<span>nitial concentration</span> = 0.311
<span>C = -x,x,x </span>
<span>E = 0.311-x,x,x

</span>KNO2 ====>K+ + NO2- 
<span>Initial concentration = 0.189 </span>
<span>C= -0.189,0.189,0.189 </span>
E = 0,0.189,0.189
 
6 0
3 years ago
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