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dimaraw [331]
3 years ago
9

Please help.The question and the answer choices are in the picture.

Mathematics
1 answer:
Marianna [84]3 years ago
5 0
Total mass = 6.7134  * 10^-1

= 0.67 grams
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What is the scale factor solve of x
Natasha_Volkova [10]
The scale factor is 2

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PLEASE HELP THESE ARE MY ONLY POINT ;-; PLEASE
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Answer:

a) max 12000 , min 0

b) no solution

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Write an equation in slope intercept form given the following m = 5/4 and passing through (- 4, - 3)
raketka [301]
Y = 5/4x + 2


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2 years ago
The Polygons below are similar. Find the value of x. A. 4.5 B. 7.5 C. 12 D. 16
koban [17]
I'm pretty sure that it is C. 12 
3 0
2 years ago
Consider the function below, which has a relative minimum located at (-3 , -18) and a relative maximum located at (1/3, 14/17).
leonid [27]
First of all, when I do all the math on this, I get the coordinates for the max point to be (1/3, 14/27).  But anyway, we need to find the derivative to see where those values fall in a table of intervals where the function is increasing or decreasing.  The first derivative of the function is f'(x)=-3x^2-8x+3.  Set the derivative equal to 0 and factor to find the critical numbers. 0=-3x^2-8x+3, so x = -3 and x = 1/3.  We set up a table of intervals using those critical numbers, test a value within each interval, and the resulting sign, positive or negative, tells us where the function is increasing or decreasing.  From there we will look at our points to determine which fall into the "decreasing" category.  Our intervals will be -∞<x<-3, -3<x<1/3, 1/3<x<∞.  In the first interval test -4. f'(-4)=-13; therefore, the function is decreasing on this interval.  In the second interval test 0. f'(0)=3; therefore, the function is increasing on this interval.  In the third interval test 1. f'(1)=-8; therefore, the function is decreasing on this interval.  In order to determine where our points in question fall, look to the x value.  The ones that fall into the "decreasing" category are (2, -18), (1, -2), and (-4, -12).  The point (-3, -18) is already a min value.
8 0
3 years ago
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