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4 years ago

Is a trapezoid a 2 dimensional figure?

2 answers:

8 0

A trapezoid can be drawn on 2 dimensional surfaces like board. So it is a 2D shape.

Tju [1.3M]4 years ago

5 0

If it can be drawn on a 2D surface such as a board, or a page etc. then it's a 2D shape. So yes a trapezoid is a 2D shape.

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The quotient of 45% -31. - 15) and a polynomial is (-3). What is the pokyrıcaiak

alexira [117]

Answer:

Step-by-step explanation:

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3 years ago

Joey had eight pencils in the morning. He gave some pencils away to friends who needed them. To determine the number of pencils

pshichka [43]

Answer : Subtract

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2 years ago

How is the Distributive Property used to simplify operations with scientific notation

Citrus2011 [14]

Answer:

See explanation

Step-by-step explanation:

Let a,b, and c be real numbers.

The distributive property says that:

$a(b + c) = ab + ac$

Assuming we want to simplify:

$10(5*10^{-1}+150*10^{-3})$

We apply the distributive property to get:

$10(5*10^{-1}+150*10^{-3}) = 5*10^{-1} \times 10+150*10^{-3} \times 10$

We can now use rules of exponents to simplify further:

$10(5*10^{-1}+150*10^{-3}) = 5*10^{-1} \times 10^{1} +150*10^{-3} \times 10^{1}$

$10(5*10^{-1}+150*10^{-3}) = 5*10^{-1 + 1} +150*10^{-3 + 1}$

$10(5*10^{-1}+150*10^{-3}) = 5*10^{0} +150*10^{-2}$

$10(5*10^{-1}+150*10^{-3}) = 5*1+1.50*10^{-2}x {10}^{2}$

$10(5*10^{-1}+150*10^{-3}) = 5*1+1.50*10^{-2 + 2}$

$10(5*10^{-1}+150*10^{-3}) = 5+1.50*10^{0} = 6.5 \times {10}^{0}$

4 0

3 years ago

Four times Greg's age, decreased by 3 is equal to 3 times Greg's age, increased by 7. How old is Greg? Not Multiple choice

Jet001 [13]

Ok. So what I did was I chose a number that would be easy to manipulate The number I chose was 10, I then multiplied it by 4 to get 40, then subtracted 3 to get 37 - that was the first part of the question. The second part wanted me to take the same number, multiply it by 3 and then add 7. So 10 multiplied by 3 is of course 30 and then you just add 7 to get 37. Hey look! Its a match! I hope this helps.

P.S. - If you think I did a good job I would love it if you went to my YouTube channel to see if I can help you more there. Here is the link: https://www.youtube.com/channel/UCG0zQcSsxZ2mu-OnZRdI2-Q . I hope to see you there!

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3 years ago

The relationship 1/sin(θ) is equivalent to which of the following trigonometric functions?

Helga [31]

$\bf sin(\theta)=\cfrac{1}{csc(\theta)}
\qquad 
% cosine
cos(\theta)=\cfrac{1}{sec(\theta)}
\qquad 
% tangent
tan(\theta)=\cfrac{sin(\theta)}{cos(\theta)}
\\\\\\
% cotangent
cot(\theta)=\cfrac{cos(\theta)}{sin(\theta)}
\qquad 
% cosecant
\boxed{csc(\theta)=\cfrac{1}{sin(\theta)}}
\qquad 
% secant
sec(\theta)=\cfrac{1}{cos(\theta)}$

6 0

4 years ago

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