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Semmy [17]
3 years ago
12

What is the maximum mass that can hang without sinking from a 50-cm diameter Styrofoam sphere in water

Physics
1 answer:
ddd [48]3 years ago
8 0

This question is incomplete, the complete question is;

Styrofoam has a density of 32kg/m³.

What is the maximum mass that can hang without sinking from a 50-cm diameter Styrofoam sphere in water

Answer: the required maximum mass is 63.3459 kg

Explanation:

Given that;

diameter d = 50 cm = 0.5 m

radius r = 0.5 / 2 = 0.25 m

Styrofoam density = 32kg/m³

Volume of sphere V = 4/3 πr³.

we substitute

V = 4/3 π(0.25)³

V = 0.06544 m³

Mass of sphere M = Volume × Density

we substitute

Mass of sphere M = 0.06544 m³ × 32kg/m³

Mass of Sphere M = 2.09408 kg

Mass of the water it displace will be;

volume × density

we know that density of water = 1000 kg/m³

so

Mass of the water it displace = 0.06544 m³ × 1000kg/m³

= 65.44 kg

Now the difference between mass of water and mass of the Styrofoam will be the amount of mass that the sphere can support

so

65.44 kg - 2.09408 kg = 63.3459 kg

Therefore, the required maximum mass is 63.3459 kg

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The study 'characterizing vibration-assisted atomic force based nanomachining' aims to elucidate nanomachine properties for heterogeneous materials.

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8 0
1 year ago
Hey! I found this question quite interesting. Check it out - https://www.meritnation.com/ask-answer/question/to-raise-a-200kg-st
Yanka [14]

Answer:

yes yes so do I

6 0
3 years ago
How much pressure is applied to the ground
statuscvo [17]

Answer:

Pressure applied by the man= 285103.125 Pa  or 41.35 lb/in^{2}

Explanation:

Pressure is defined as the perpendicular force applied per unit area.

i.e.  Pressure=\frac{Force}{Area}

Now, Force= mg

where, m = mass of the body(man) = 93 kg

g = acceleration due to gravity of Earth = 9.81 m/{s^{2}}

Area covered is equal to the area of both stilts(a man generally stands on two feet)

therefore Area=2(0.04)^{2} m^{2}

and putting in the values, we get,

Pressure=\frac{93\times9.81}{2\times(0.04)^{2}}Nm^{-2}=285103.125Nm^{-2}

Now we need to convert to our required units:

1Nm^{-2}=1Pa\\1Pa=0.000145038lb/in^{2}

(We can get the above result by individually converting kg to lb and meters to inches respectively)

Using the above relations we get,

Pressure=285103.125Pa=0.000145038\times285103.125lb/in^{2}=41.35lb/in^{2}

7 0
3 years ago
#1 a person weighs 540n on earth what is the persons mass.
bixtya [17]

Answer:

G on earth =10N/Kg

W= mg

540= m x 10

m = 540/10

m= 54 Kg

W= mg

W= 66 x 10

W= 660 N

G on moon =1.6 N/Kg

#1

W= mg

W= 54 x 1.6

W=86.4 N

#2

W=mg

W= 66 x 1.6

W= 105.6 N

8 0
2 years ago
The reason galaxies that are distant from our galaxy move away from our galaxy more rapidly than those that are near is:
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The reason galaxies that are distant from our galaxy move away from our galaxy more rapidly is more space expands between us and distant galaxies.

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4 0
2 years ago
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