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Semenov [28]
4 years ago
10

George has a mass of 30 kg. He sits 1.4 m from the axis of rotation of a see-saw. If Susie has a mass of 27 kg, how far from the

axis of rotation should she sit on the other side of the see-saw to keep it in static equilibrium? Assume the center of mass of the see-saw is above the axis of rotation. g
Physics
1 answer:
aivan3 [116]4 years ago
3 0

Answer:

d ₂ = 1.56 m : horizontal distance from where Susie sits to the axis of rotation.

Explanation:

M = F * d   Formula (1)

F is the magnitude of said force (N)

d: distance to the axis of rotation

The direction of the moment is determined by the direction of rotation and can be assumed positive in a counterclockwise direction and negative in the clockwise direction.

Forces on the see-saw

W: Weight: in the vertical direction and down

W₁= m₁*g =  30 kg*9.8 m/s²= 294 N

W₂= m₂*g =  27 kg*9.8 m/s²= 264.6 N    

Distances of the forces to the axis of rotation

d₁ =  1.4 m :distance from where W₁ is located to the axis of rotation

d₂ :  distance from where W is located to the axis of rotation

Problem development

For static equilibrium the sum of moments around the axis of rotation is zero:

∑M =0

W₁*d₁ - W₂*d₂ = 0

W₁*d₁ = W₂*d₂

294*1.4  = 264.6*d₂

411.6= 264.6*d₂

d₂ =( 411.6) / (264.6)

d ₂= 1.56 m

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3 years ago
Convert: Thermal conductivity value of 0.3 Btu/(h ft°F) to W/(m °C). Surface heat transfer coefficient value of 105 Btu/(h ft2 o
Finger [1]

Answer:

0.3 Btu/(h ft °F) = 0.5189 W/(m°C)

105 Btu/(h ft² °F) = 596.2215 W/(m²°C)

Explanation:

<u>Thermal conductivity of a substance is defined as the measure of the tendency of the substance to conduct heat.</u>

<u>The SI unit of thermal conductivity is W.m⁻¹K⁻¹ .</u>

From the question , 0.3 Btu/(h ft °F) is to be converted to W/(m°C)

Thus,

1 Btu/(h ft °F) = 1.7296 W/(m°C)

So,

0.3 Btu/(h ft °F) = 1.7296×0.3 W/(m°C) = 0.5189 W/(m°C)

Thus,

<u>0.3 Btu/(h ft °F) = 0.5189 W/(m°C)</u>

<u>Heat transfer coefficient is defined as proportionality constant between heat flux (Thermal power per unit area) and the temperature difference of the substance for that flow of heat.</u>

<u>The SI unit of thermal conductivity is W.m⁻²K⁻¹ .</u>

From the question , 105 Btu/(h ft² °F) is to be converted to W/(m²°C)

Thus,

1 Btu/(h ft² °F) = 5.6783 W/(m²°C)

So,

105 Btu/(h ft² °F) = 5.6783×105 W/(m²°C) = 596.2215 W/(m²°C)

Thus,

<u>105 Btu/(h ft² °F) = 596.2215 W/(m²°C)</u>

3 0
3 years ago
A magnetic field is entering into a coil of wire with radius of 2(mm) and 200 turns. The direction of magnetic field makes an an
frozen [14]

Answer:

a) <em>2.278 x 10^-5 volts</em>

b) <em>1.139 x 10^-6 Ampere</em>

c) <em>2.59 x 10^-11 W</em>

Explanation:

The radius of the wire r = 2 mm = 0.002 m

the number of turns N = 200 turns

direction of the magnetic field ∅ = 25°

magnetic field strength B = 0.02 T

varying time = 2 sec

The cross sectional area of the wire = \pi r^{2}

==> A = 3.142 x 0.002^{2} = 1.257 x 10^-5 m^2

Field flux Φ = BA cos ∅ = 0.02 x 1.257 x 10^-5 x cos 25°

==> Φ = 2.278 x 10^-7 Wb

The induced EMF is given as

E = NdΦ/dt

where dΦ/dt = (2.278 x 10^-7)/2 = 1.139 x 10^-7

E = 200 x 1.139 x 10^-7 = <em>2.278 x 10^-5 volts</em>

<em></em>

<em></em>

b) If the two ends are connected to a resistor of 20 Ω, the current through the resistor is given as

I = E/R

where R is the resistor

I = (2.278 x 10^-5)/20 = <em>1.139 x 10^-6 Ampere</em>

<em></em>

<em></em>

<em> </em>c) power delivered to the resistor is given as

P = IE

P = (1.139 x 10^-6) x (2.278 x 10^-5) = <em>2.59 x 10^-11 W</em>

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denis23 [38]
Answer: It’s c
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