Answer:
Assuming air resistance is negligible, all of the potential energy that the object has at the top of the ramp is converted into kinetic energy by the time it gets to the bottom of the ramp. This is because no matter what path the object takes to move the 5m vertically (ie. falling straight down v. sliding on the ramp), gravity does the same amount of work on it.
Thus, calculate the total amount of potential energy at the top of the ramp:
Ep=mgh
Ep=4(9.81)5
Ep=196.2 Joules
Because all of this potential energy is converted into kinetic energy in the object by the bottom of the ramp, the object hits the spring with 196.2J of energy.
By using the formula for elastic potential energy, you can calculate exactly how far the spring compresses.
196.2=(1/2)k(x^2)
392.4=(350)(x^2)
1.1211=x^2
sqrt(1.1211)=x
x=1.059m
As for the last part of the question, after the object compresses the spring fully and stops momentarily, the spring converts it's elastic potential energy back into kinetic energy in the object and pushes it away again.
Explanation:
Answer: a) 112.88 * 10^3 N/C; b) The electric field point outward from the center of the sphere.
Explanation: In order to solve this problem we have to use the gaussian law so we use a gaussian surface at r=0.965 m and the electric flux is equal to Q inside/εo
E* 4*π*r^2= Q inside/εo
E= k*Q inside/r^2= 9*10^9*(6.53+5.15)μC/(0.965)^2=122.88 * 10 ^3 N/C
Sand dunes during the Dust Bowl are an example of windward.
The sand dunes are formed due to high movement of wind in the deserts which make dunes in the direction where wind is moving. Windward refers to facing the wind or situated on the side facing the wind so in those regions where the wind moves bring sand with itself and make dunes in that area so we can conclude that sand dunes are formed in the windward regions.
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Answer:
v = 27.456 m/s
Explanation:
The support pressure needed of the water in the straw can be calculated by the formula
Given that,
P = r*g*h
= 1000*9.8*0.05 Pa.= 490 Pa
This pressure is compensated by 0.5*r*v^2 of the air,
Hence,
0.5*1.3*v^2 = 490
velocity of air blown into the straw =
v = 27.456 m/s
Scientific form = 6.5 x 109.