Answer:
A) ΔU = 3.9 × 10^(10) J
B) v = 8420.75 m/s
Explanation:
We are given;
Potential Difference; V = 1.3 × 10^(9) V
Charge; Q = 30 C
A) Formula for change in energy of transferred charge is given as;
ΔU = QV
Plugging in the relevant values gives;
ΔU = 30 × 1.3 × 10^(9)
ΔU = 3.9 × 10^(10) J
B) We are told that this energy gotten above is used to accelerate a 1100 kg car from rest.
This means that the initial potential energy will be equal to the final kinetic energy since all the potential energy will be converted to kinetic energy.
Thus;
P.E = K.E
ΔU = ½mv²
Where v is final velocity.
Plugging in the relevant values;
3.9 × 10^(10) = ½ × 1100 × v²
v² = [7.8 × 10^(8)]/11
v² = 70909090.9090909
v = √70909090.9090909
v = 8420.75 m/s
Answer:
The resultant velocity of the jet as a vector in component form 426.87 mi/hr 5.36 degrees North.
Explanation:
Vectors are quantities that have their magnitude and direction .
Sketching out the problem given, by using straight lines to represent each of the vectors, we will have a right angled triangle as shown below.
The solution can be obtained by applying Pythagoras theorem to
resolve the vectors.
Velocity of jet plane = 425 mi/hr
velocity of air = 40 mi/hr
Resultant of the vectors =
mi/hr
Vector direction =
hence the velocity is 426.87 mi/hr in a direction 5.36 degrees inclined Northward
Answer:

Explanation:
= Actual wavelength = 
= Relative permittivity = 1.44
The observed wavelength in the glass is given by

The wavelength lies in the range of green light.
Hence, the observed color of light is 
The atomic mass of an atom ... in Atomic Mass Units ... is the sum of the numbers of protons and neutrons in its nucleus.
Answer:
d. none of these
Explanation:
From the given information:
Let assume that Percival catches Sir Rodney's horse in time "t" after covering a certain distance "s"
Then, using the second equation of motion:

FOR Percival, we have:

FOR Sir Rodney;


Equating both equations together; we have:
0.3t² = 3t
0.3t² - 3t = 0
0.3t(t - 10) = 0
If Percival's position at rest = 0
Then; t = 10 s.