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coldgirl [10]
3 years ago
9

When cleaning up a local beach, students found many different particles that were in the water that affected the shoreline, like

litter and gasoline. Which of the following describe how these items would need to separated from the water? Why?
A. Both gasoline and litter would need to be chemically separated from the water, because both form new bonds with the water.


B. Litter would need to be physically separated with water and gasoline would need to be chemically separated from water, because both form a mixture with the water.


C. Both gasoline and litter would need to be chemically separated from the water, because neither bonds with the water.


D. Both gasoline and litter would need to be physically separated from the water, because neither bonds with the water.


(p.s. Do teachers know about this? like fr)
Physics
1 answer:
Wewaii [24]3 years ago
4 0

The correct answer is D,

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On a cross-country trip, a couple drives 500 mi in 10 h on the first day, 380 mi in 8.0 h on the second day, and 600 mi in 15 h
Zepler [3.9K]

We know that the average speed is simply the ratio of the total distance travelled over the total duration of the trip.

total distance = 500 mi + 380 mi + 600 mi

total distance = 1,480 mi

 

total time = 10 h + 8 h + 15 h

total time = 33 h

 

So the average speed is therefore:

average speed = 1,480 mi / 33 h

<span>average speed = 44.85 mi / h</span>

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3 years ago
What conclusions can you draw about the connection between the Sun’s altitude and the latitude of the observer on seasonal chang
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Answer:

Explanation:

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But when the sun is at higher altitudes we receive less denser rays of the sun and hence we have less heat on the earth on an average.

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6 0
2 years ago
To practice Problem-Solving Strategy 15.1 Mechanical Waves. Waves on a string are described by the following general equation y(
DerKrebs [107]

Answer:

0.0549 m

Explanation:

Given that

equation y(x,t)=Acos(kx−ωt)

speed  v = 8.5 m/s

amplitude A = 5.5*10^−2 m

wavelength λ   = 0.5 m

transverse displacement = ?

v = angular frequency / wave number

and

wave number = 2π/ λ

wave number =  2 * 3.142 / 0.5

wave number = 12.568

angular frequency = v k

angular frequency = 8.5 * 12.568

angular frequency = 106.828 rad/sec ~= 107 rad/sec

so

equation y(x,t)=Acos(kx−ωt)

y(x,t)= 5.5*10^−2 cos(12.568 x−107t)

when x =0 and and t = 0

maximum y(x,t)= 5.5*10^−2 cos(12.568 (0) − 107 (0))

maximum y(x,t)= 5.5*10^−2  m

and when x =  x = 1.52 m and t = 0.150 s

y(x,t)= 5.5*10^−2 cos(12.568 (1.52) −107(0.150) )

y(x,t)= 5.5*10^−2 × (0.9986)

y(x,t) = 0.0549 m

so the transverse displacement is  0.0549 m

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podryga [215]

Answer:

Due to lower risk of injury or damage.

Explanation:

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