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Goryan [66]
4 years ago
10

Unknown element x has four energy levels, five valence electrons, and is a metalloid. what is elements x?

Chemistry
1 answer:
kykrilka [37]4 years ago
8 0

Answer:

Element X is Arsenic (As)

Explanation:

  • Elements in the periodic table are either metals, non-metals or metalloids.
  • Metals are elements that react by losing electrons to obtain a stable configuration and form cation.
  • Non-metals are those elements that react by gaining electrons to form a stable configuration and form anion.
  • Metalloids are elements in the periodic table that have both metallic and non-metallic properties.
  • Examples of metalloids include Selenium, Arsenic, Boron, etc.
  • Arsenic is a metalloid in period 4 (four energy levels) with five valence electrons.
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Water vapor is condensed steam. <br><br> True <br> False
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8 0
3 years ago
If the rate of decomposition of ammonia, NH3, at 1150 K is 2.10 x 10-6 mol/L/s, what is the
Alina [70]

Answer:

3.15 × 10⁻⁶ mol H₂/L.s

1.05 × 10⁻⁶ mol N₂/L.s

Explanation:

Step 1: Write the balanced equation

2 NH₃ ⇒ 3 H₂ + N₂

Step 2: Calculate the rate of production of H₂

The molar ratio of NH₃ to H₂ is 2:3. Given the rate of decomposition of NH₃ is 2.10 × 10⁻⁶ mol/L.s, the rate of production of H₂ is:

2.10 × 10⁻⁶ mol NH₃/L.s × 3 mol H₂/2 mol NH₃ = 3.15 × 10⁻⁶ mol H₂/L.s

Step 3: Calculate the rate of production of N₂

The molar ratio of NH₃ to N₂ is 2:1. Given the rate of decomposition of NH₃ is 2.10 × 10⁻⁶ mol/L.s, the rate of production of N₂ is:

2.10 × 10⁻⁶ mol NH₃/L.s × 1 mol N₂/2 mol NH₃ = 1.05 × 10⁻⁶ mol N₂/L.s

3 0
3 years ago
How do I calculate the molecular weight of Mg(OH)2?
vodomira [7]

The molecular weight of Mg(OH)2 : 58 g/mol

<h3>Further explanation</h3>

Given

Mg(OH)2 compound

Required

The molecular weight

Solution

Relative atomic mass (Ar) of element : the average atomic mass of its isotopes  

Relative molecular weight (M)  : The sum of the relative atomic mass of Ar  

M AxBy = (x.Ar A + y. Ar B)  

So for Mg(OH)2 :

= Ar Mg + 2 x Ar O + 2 x Ar H

= 24 g/mol + 2 x 16 g/mol + 2 x 1 g/mol

= 24 + 32 + 2

= 58 g/mol

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