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3 years ago

Unknown element x has four energy levels, five valence electrons, and is a metalloid. what is elements x?

Chemistry

1 answer:

kykrilka [37]3 years ago

8 0

Answer:

Element X is Arsenic (As)

Explanation:

Elements in the periodic table are either metals, non-metals or metalloids.
Metals are elements that react by losing electrons to obtain a stable configuration and form cation.
Non-metals are those elements that react by gaining electrons to form a stable configuration and form anion.
Metalloids are elements in the periodic table that have both metallic and non-metallic properties.
Examples of metalloids include Selenium, Arsenic, Boron, etc.
Arsenic is a metalloid in period 4 (four energy levels) with five valence electrons.

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Please explain your answer! Thanks!

Yuri [45]

Hello Gary!
*Sorry if I'm late*

Your answer is going to be 65.
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Hope this helps!
Have a nice day :D

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2 years ago

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A 10.0cm3 volume of alcohol has a mass of 7.05g. What the density

VMariaS [17]

A 10.0cm3 volume of alcohol has a mass of 7.05g. $0.705 \frac{g}{c m^{3}}$ is the density

Answer: $0.705 \frac{g}{c m^{3}}$

Explanation:

The ratio between the mass of a substance and its unit volume is referred as density.

$\text {Density}=\frac{\text { mass }}{\text { volume }}=\frac{7.05 g}{10.0 \mathrm{cm}^{3}}=0.705 \frac{g}{\mathrm{cm}^{3}}$ is the Answer

Note:

1000 g = 1 kg

100 cm = 1 m

When we used to transform the given values into S.I units, then

$\text {Density}\left(\frac{k g}{m^{3}}\right)=\frac{\text {Mass}(k g)}{\text {Volume}\left(m^{3}\right)}$

Alcohol’s volume can be written as, $10.0 c m^{3} = 10 \times 10^{-2} m^{3}$

Alcohol’s mass can denote as, $7.05 g = 7.05 \times 10^{-3} \mathrm{kg}$

Then, $\text { Density }\left(\frac{k g}{m^{8}}\right)=\frac{, 00705(k g)}{0.1\left(m^{3}\right)} = .0705 \frac{\mathrm{kg}}{\mathrm{m}^{\mathrm{s}}}$

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3 years ago