Explanation:
IM PRETTY SURE IT IS D !! IF ITS WRONG IM SORRY THAT WHAT
I GOT
Answer:
The water will absorb 1004.16 Joule of heat
Explanation:
Step 1: Data given
Mass of the metal = 58.00 grams
Temperature of the metal = 100.00 °C
Mass of water = 60.00 grams
Temperature of water = 18.00 °C
Final temperature = 22.00 °C
Specific heat of water = 4.184 J/g°C
Step 2: Calculate the amount of heat absorbed by the water in joules
Q = mass *specific heat *ΔT
⇒ with Q = the heat absorbed by water
⇒ with mass of water = 60.00 grams
⇒ with specific heat of water = 4.184 J/g°C
⇒ with ΔT = The change in temperature of water = T2 - T1 = 22 - 18 = 4.0 °C
Q = 60.00 * 4.184 J/g°C * 4.0 °C
Q = 1004.16 J
The water will absorb 1004.16 Joule of heat
Answer:
pH is 7.60
Explanation:
Let's think the equations:
HClO + H₂O ⇄ ClO⁻ + H₃O⁺
As every weak acid, we make an equilbrium
The salt is dissociated in solution
NaClO → Na⁺ + ClO⁻
HClO + H₂O ⇄ ClO⁻ + H₃O⁺
Initially 0.3m 0.35m
We have the moles of acid, and the moles of conjugate base.
Reacts x X X
Some amount has reacted, so I obtained (in equilibrium) the moles of base + that amount, and the same amount for H₃O⁺ (ratio is 1:1)
HClO + H₂O ⇄ ClO⁻ + H₃O⁺
0.3 - x 0.35 + x x
Let's make the expression for Ka
Ka = [ClO⁻] . [H₃O⁺] / [HClO]
(we don't add water, because it is included in Ka)
2.9x10⁻⁸ = (0.35+x).x / (0.3-x)
Ka is in order of 10⁻⁸, I can assume that 0.3-x is 0.3 and 0.35 +x =0.3
2.9x10⁻⁸ = (0.35)x / (0.3)
(2.9x10⁻⁸ . 0.3) /0.35 = x
2.48x10⁻⁸ = x
This is [H₃O⁺]
For pH = - log [H₃O⁺]
pH = 7.60
Answer is in the question light-year. this is the distance light travels in one year. A year is defined as the amount of time it takes for the earth to make its trip around the sun. So if it took 8 light-years then it took...
Answer:
0.576M and 0.655m
Explanation:
<em>...Dissolves 15.0g of styrene (C₈H₈) in 250.mL of a solvent with a density of 0.88g/mL...</em>
<em />
Molarity is defined as moles of solute (Styrene in this case) per liter of solution whereas molality is the moles of solute per kg of solvent. Thus, we need to find the moles of styrene, the volume in liters of the solution and the mass in kg of the solvent as follows:
<em>Moles styrene:</em>
Molar mass C₈H₈:
8C = 12.01g/mol*8 = 96.08g/mol
8H = 1.005g/mol* 8 = 8.04g/mol
96.08g/mol + 8.04g/mol = 104.12g/mol
Moles of 15.0g of styrene are:
15.0g * (1mol / 104.12g) = 0.144 moles of styrene
<em>Liters solution:</em>
250mL * (1L / 1000mL) = 0.250L
<em>kg solvent:</em>
250mL * (0.88g/mL) * (1kg / 1000g) = 0.220kg
Molarity is:
0.144 moles / 0.250L =
<h3>0.576M</h3>
Molality is:
0.144 moles / 0.220kg =
<h3>0.655m</h3>
