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2 years ago

Complete the pie chart formula. (Category/ ) × 360° = Portion of graph.

Chemistry

1 answer:

iVinArrow [24]2 years ago

4 0

Answer:

A toy car has a 1.5-A current, and its resistance is 2 . How much voltage does the car require?

Explanation:

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Determine if each statement is True or False. [ Select ] Central atoms with four electron groups will be sp3 hybridized. [ Selec

meriva

Answer:

Central atoms with four electron groups will be sp3 hybridized. True

Hybrid orbitals are delocalized over the entire molecule. False

The number of hybrid orbitals is equal to the number of atomic orbitals that are blended together. True

Atoms with a single pi bond and an octet are sp2 hybridized. True

Sometimes oxygen atoms will be sp3d hybridized in organic molecules. False

All resonance structures must be considered when assigning hybridization. False

Explanation:

When a central atom has four electron groups attached to it, then it must be sp3 hybridized. This is the case in ammonia, water, hydrogen sulphide, methane etc.

Hybridization is a valence bond concept while delocalization is a molecular orbital theory concept. Hybridized orbitals are localized on central atoms in a molecule while delocalized orbitals spread across the entire molecule.

According to valence bond theory, the number of atomic orbitals that combined to give hybrid orbitals must be equal to the number of hybrid orbitals formed.

When an atom has a single pi bond and on octet of electrons, then it must be sp2 hybridized. Remember that in ethene for instance, carbon has one pi bond and an octet of electrons.

Oxygen has an empty n=3 level hence it can not have d-orbitals involved in hybridization.

The electron domain geometry of the molecule is considered when assigning hybridization and not the resonance structures. All the resonance structures must have the central atom in the same hybridization state.

8 0

3 years ago

Which organelle in the table is correctly matched with its function?<br> which one is it??

Papessa [141]

Answer:

$\huge\boxed{\sf Ribosomes}$

Explanation:

<h3>Organelles and their function:</h3><h3><u>Lysosomes:</u></h3>

Lysosomes functions in the digestion of food of the cell.
It contains hydrolytic enzymes.

<h3><u>Vacuole:</u></h3>

Vacuole mostly functions in storage.

<h3><u>Mitochondrion:</u></h3>

Mitochondrion is the power house of the cell.

<h3><u>Ribosome:</u></h3>

Ribosome functions in protein synthesis.

$\rule[225]{225}{2}$

4 0

1 year ago

Write me a brief description of a Nerve Signal. (Only one sentence)

astraxan [27]

Description of a nerve signal

The nerve signal, or action potential, is a coordinated movement of sodium and potassium ions across the nerve cell membrane. Here's how it works: As we discussed, the inside of the cell is slightly negatively charged (resting membrane potential of -70 to -80 mV).

7 0

2 years ago

Consider three gases: Ar, SF6, and Cl2. If 50.0 grams of these gases are placed in each of three identical containers, which con

adoni [48]

The ideal gas law:
$pV=nRT \Rightarrow p=\frac{nRT}{V}$
p - pressure, n - number of moles, R - the gas constant, T - temperature, V - volume

The volume and temperature of all three containers are the same, so the pressure depends on the number of moles. The greater the number of moles, the higher the pressure.
The mass of gases is 50 g.

$Ar \\
M \approx 39.948 \ \frac{g}{mol} \\
n=\frac{50 \ g}{39.948 \ \frac{g}{mol}} \approx 1.25 \ mol \\ \\
SF_6 \\
M \approx 146.06 \ \frac{g}{mol} \\
n=\frac{50 \ g}{146.06 \ \frac{g}{mol}} \approx 0.34 \ mol \\ \\
Cl_2 \\
M=70.9 \ \frac{g}{mol} \\
n=\frac{50 \ g}{70.9 \ \frac{g}{mol}} \approx 0.71 \ mol$

The greatest number of moles is in the container with Ar, so there is the highest pressure.

4 0

3 years ago

Acetic acid (HC2H3O2) is the active ingredient in vinegar. Calculate the mass percent composition of O in acetic acid.

skelet666 [1.2K]

Answer:

53.29% of acetic acid is Oxygen

Explanation:

Step 1: Given data

Acetic acid it's molecular formula is HC2H3O2. This means it consists of 3 elements Carbon, Hydrogen and oxygen.

Step 2: the molar masses

The molecular mass of acetic acid is:

4* H = 4* 1.01 g/mole

2* C = 2*12 g/mole

2*O = 2* 16 g/mole

Total molar mass = 4+ 24+32 = 60.052 g/mole

Step 3: Calculate the mass percent

32 g of the 60.052 g is Oxygen

(32/60.052) *100% = 53.29%

53.29% of acetic acid is Oxygen.

7 0

3 years ago

Read 2 more answers