Answer:
The maximum speed of the mass is 1.67 m/s.
Explanation:
We have,
Mass of object is 34 g or 0.034 kg
Spring constant of the spring is 78.1 N/m
Amplitude attained by the object is 3.5 cm or 0.035 m
It is required to find the maximum speed of the object in this spring mass system. The maximum speed is given by :
Plugging all the values in above formula,
So, the maximum speed of the mass is 1.67 m/s.
When 2 electric charges are place close to each other they experience a force between them. This force may be repulsive or attractive depending on the type of charges involved.
The magnitude of this force depend on the quantity of individual charges and the distance between them.
The force is defined by the <em>Coulomb's law</em> states that: <em>The magnitude of the electrostatic force of attraction or repulsion between two point charges is directly proportional to the product of the magnitudes of charges and inversely proportional to the square of the distance between them.</em>
The formula for calculating the force between 2 electric charges is ;
F = (kq₁q₂)/d²
Where k is the proportionality constant known as Coulomb's constant,
q₁ and q₂ are the charges and
d is the distance between q₁ and q₂.
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If he does not use the lenses, his near point will be 66.7 cm. For him to read a material at 50 cm, he has to use a lens of 2.0D.
<h3>What is the near point?</h3>
The near point is the nearest area which a person can see or have distinct vision. The focal length of the lens is f = 100/2.5 = 40cm
Then;
1/40 = -1/v + 1/25
1/v = 1/25 - 1/40
v = 66.7 cm
Also, for the purpose of reading at 50 cm
1/f = -1/50 + 1/25
1/f = 1/25 - 1/50
f = 50cm
The power of this lens is;
100/50 cm = 2 D
Learn more about lens: brainly.com/question/1503351
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