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Ksivusya [100]
3 years ago
12

In which of the following cases is work being done on an object? Question 2 options: Pushing against a locked door Carrying a bo

x down a corridor Pulling a trailer up a hill Suspending a heavy weight with a strong chain???
Physics
1 answer:
astra-53 [7]3 years ago
3 0

The answer would be:

Pulling a trailer up a hill

Here is why:

In physics, work is computed by the formula:

W = Fd or F(cosΘ)d

Where: F = Force applied on the object

            d =displacement

So in order for work to be done, the object needs to be displaced. In the case of the trailer, the trailer is being pulled and it is travelling in the direction of the force applied.

The other options the object is not displaced. Even if you exert a force, if the displacement remains the same, then it will always be zero, so the force times displacement will be 0, hence no work is done.

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Can some answer 7 a and b please
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Answer:

a.After 15 second Mr Comer's speed =  1.7 m/s

b.Distance travelled by Mr.Comer in 15 seconds  =   18.75\ m

Explanation:

a. Lets recall our first equation of motion V_{f} =V_{i} + at

Now we know that V_{i} = 0.8m/s , a = 0.06\ m/s^2 and

t = 15 \ sec

Plugging the values we have.

V_{f} =V_{i} + at

V_{f} =0.8 + 0.06 \times 15

V_{f} =0.8+ 0.9

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Then Mr.Comer's speed after 15 sec = 1.7ms^-1

b.

Lets find the distance and recall our third equation of motion.

V_{f} ^2-V{i}^2 = 2as

So s = distance covered.

Dividing both sides with 2a we have.

\frac{V_{f} ^2-V{i}^2}{2a} = 2as

Plugging the values.

\frac{(1.7)^2-(0.8)^2}{2\times0.06} = 2as

s= 18.75\ m

So Mr.Comer will travel a distance of s= 18.75\ m.

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Hope this helps!

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