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eduard
3 years ago
12

Vector 1 has a magnitude of 24 m and is pointed to the west. Vector 2 has a magnitude of 11 and is pointed to the north. What is

the magnitude and direction of the resultant vector produced by these two?
Physics
2 answers:
erica [24]3 years ago
7 0

Answer:

Explanation:

A = 24 m west

B = 11 m north

Write these in vector form

\overrightarrow{A}= - 24\widehat{i}

\overrightarrow{B}= 11\widehat{j}

Resultant of two vectors is

\overrightarrow{R} = \overrightarrow{A} + \overrightarrow{B}

\overrightarrow{R}= - 24 \widehat{i} + 11\widehat{j}

Magnitude of resultant

R=\sqrt{24^{2}+11^{2}}

R = 26.4 m

Direction

tan θ =  - 11 / 24

θ = - 24.6°

Vedmedyk [2.9K]3 years ago
6 0

Explanation:

It is given that,

Vector 1 has a magnitude of 24 m and is pointed to the west.

Vector 2 has a magnitude of 11 and is pointed to the north.

Let v is the resultant of two vectors. The resultant of two vectors is given by :

v=\sqrt{v_1^2+v_2^2}

v=\sqrt{24^2+11^2}

v = 26.4 m

To find direction,

\theta=tan^{-1}(\dfrac{v_2}{v_1})

\theta=tan^{-1}(\dfrac{11}{24})

\theta=24.62^{\circ}

So, the magnitude and direction of the resultant vector produced by these two is 26.4 m and 24.62 degrees respectively. Hence, this is the required solution.

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