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Ratling [72]
3 years ago
11

1. Which combinations of substances resulted in a chemical change?

Chemistry
1 answer:
MrRissso [65]3 years ago
6 0

Answer:

. For each metal that participated in a chemical change, write the type of metal it is, based on yourexamination of the periodic table.Answer: Ammonium Vanadate appears to be mostly a post transition metal. Manganese sulfate also hasmore post transition atoms than transition atoms. Iron nitrate is a transition metal. The cobalt nitrate is atransition metal. Copper nitrate is a transition metal. Zinc nitrate is also a transition metal.(5 points)3. Were there any metallic compounds that did not react with either the acid or the base? Write the type ofmetal, based on your examination of the periodic table.4. Make a general statement about the reactivity of the metals in this experiment.Answer: The transition metals in this experiment were all reactive when mixed with one of the twosubstances. The alkali and alkaline earth metals, however, did not react at all.

Explanation:

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Why is it important for a scientist studying greenhouse effect to know about mater,forces and energy
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8 0
3 years ago
2-phosphoglycerate(2PG) is converted to phosphoenolpyruvate (PEP) by the enzyme enolase. The standard free energy change(deltaGo
pogonyaev

Answer:

The correct option is: (D) -2.4 kJ/mol

Explanation:

<u>Chemical reaction involved</u>: 2PG ↔ PEP

Given: The standard Gibb's free energy change: ΔG° = +1.7 kJ/mol

Temperature: T = 37° C = 37 + 273.15 = 310.15 K    (∵ 0°C = 273.15K)

Gas constant: R = 8.314 J/(K·mol) = 8.314 × 10⁻³ kJ/(K·mol)     (∵ 1 kJ = 1000 J)

Reactant concentration: 2PG = 0.5 mM

Product concentration: PEP = 0.1 mM

Reaction quotient: Q_{r} =\frac{\left [ PEP \right ]}{\left [ 2PG \right ]} = \frac{0.1 mM}{0.5 mM} = 0.2

<u>To find out the Gibb's free energy change at 37° C (310.15 K), we use the equation:</u>

\Delta G = \Delta G^{\circ } + 2.303 R T log Q_{r}

\Delta G = 1.7 kJ/mol + [2.303 \times (8.314 \times 10^{-3} kJ/(K.mol))\times (310.15 K)] log (0.2)

\Delta G = 1.7 + [5.938] \times (-0.699) = 1.7 - 4.15 = (-2.45 kJ/mol)

<u>Therefore, the Gibb's free energy change at 37° C (310.15 K): </u><u>ΔG = (-2.45 kJ/mol)</u>

4 0
3 years ago
What characteristics do the elements in a group share? In a period, share?
Katyanochek1 [597]

Answer:

The elements in same period have same principle quantum number or energy shell.

The elements in same group shows similar chemical and properties.

Explanation:

Inn group:

The elements in same group i.e present in vertical column shows similar chemical properties.

The elements in same group having same number of valance electrons. while in chemical reaction bonds are break and formed and valance electrons are involved. That's why elements in same group having same number of valance electrons and shows similar chemical properties.

In period:

While as we move from left to right the number of valance electron increase by one in every element. But the electron is added in same shell which means that their physical and chemical properties are different but principal quantum number is same.

3 0
2 years ago
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