Answer
pH=8.5414
Procedure
The Henderson–Hasselbalch equation relates the pH of a chemical solution of a weak acid to the numerical value of the acid dissociation constant, Kₐ. In this equation, [HA] and [A⁻] refer to the equilibrium concentrations of the conjugate acid-base pair used to create the buffer solution.
pH = pKa + log₁₀ ([A⁻] / [HA])
Where
pH = acidity of a buffer solution
pKa = negative logarithm of Ka
Ka =acid disassociation constant
[HA]= concentration of an acid
[A⁻]= concentration of conjugate base
First, calculate the pKa
pKa=-log₁₀(Ka)= 8.6383
Then use the equation to get the pH (in this case the acid is HBrO)
Answer:
Explanation:
Your nuclear equation is
The main point to remember in balancing nuclear equations is that
Then
85 = 0 + y, so y = 85 - 0 = 0
35 = -1 + x, so x = 35 + 1 = 36
The nucleus with atomic number 36 and atomic mass 85 is krypton-85.
The nuclear equation becomes
Answer:
molality of sodium ions is 1.473 m
Explanation:
Molarity is moles of solute per litre of solution
Molality is moles of solute per kg of solvent.
The volume of solution = 1 L
The mass of solution = volume X density = 1000mL X 1.43 = 1430 grams
The mass of solute = moles X molar mass of sodium phosphate = 0.65X164
mass of solute = 106.6 grams
the mass of solvent = 1430 - 106.6 = 1323.4 grams = 1.3234 Kg
the molality =
Thus molality of sodium phosphate is 0.491 m
Each sodium phosphate of molecule will give three sodium ions.
Thus molality of sodium ions = 3 X 0.491 = 1.473 m
Answer:
The answer to the questions are as follows
Reaction B is 4426.28 times faster than reaction A
(b) Reaction B is faster.
Explanation:
To solve the question we are meant to compare both reactions to see which one is faster
The values of the given activation energies are as follows
For A
Ea = 95.00 kJ mol–1 (22.71 kcal mol–1) and
for B
Ea = 74.20 kJ mol–1 (17.73 kcal mol–1)
T is the same for both reactions and is equal to 298 k
Concentration of both reaction = 1M
The Arrhenius Law is given by
k =
Where
k = rate constant
Ea = activation energy
R = universal gas constant
T = temperature (Kelvin )
A = Arrhenius factor
Therefore
For reaction A, the rate constant k₁ is given by k₁ =
And for B the rate constant k₂ is given by k₂ =
k₁ = A×2.225×10⁻¹⁷
k₂ = A×9.850×10⁻¹⁴
As seen from the above Reaction B is faster than reaction A by (A×9.850×10⁻¹⁴)/(A×2.225×10⁻¹⁷) or 4426.28 times