Answer: Glucose is an example of carbon-based macromolecule known as carbohydrates
Explanation:
carbon based macromolecule are important cellular components and they perform a variety of functions necessary for growth and development of living organisms. There are 4 major types of carbon based molecules and these includes;
Carbohydrate
Lipids
Proteins and
Nucleic acids.
Carbon is the primary components of these macromolecules. Carbohydrate macromolecules are made up of monosaccharide, disaccharide and polysaccharides. Glucose is an example of a monosaccharide and it has two important types of functional groups: a carbonyl group and a hydroxyl group. I hope this helps. Thanks
Just for more clarification, lowercase k is the rate constant. Uppercase K is the equilibrium constant. You can actually use k to find K (equilibrium constant). K=k/k' This means that the equilibrium constant is the rate constant of the forward reaction divided by the rate constant of the reverse reaction
Because as the air hits the charcoal it becomes ash and changes color.
Answer: 218.75 kPa
Explanation:
Carbon dioxide is a gas with chemical formula CO2.
Original volume of CO2 (V1) = 3.50 L
Original pressure of CO2 (P1) = 125 kPa
New pressure of CO2 (P1) = ?
New Volume of CO2 (V2) = 2.0 L
Since pressure and volume are given while temperature is constant, apply the formula for Boyle's law
P1V1 = P2V2
3.50L X 125 kPa = P1 x 2.0L
437.5 L•kPa = 2.0L•P1
Divide both sides by 2.0L
437.5 L•kPa/2.0L = 2.0L•P1/2.0L
218.75 kPa = P1
Thus, the new pressure of carbon dioxide would be 218.75 kPa