Question

Hydrogen fluoride reacts with ammonia in an acid-base reaction:

Answer 1

Answer: a)  $HF(aq)+NH_3(aq)\rightarrow NH_4^+(aq)+F^-(aq)$

b) $NH_4^+$: conjugate acid of $NH_3$

$F^-$ : conjugate base of $HF$

Explanation:

According to the Bronsted-Lowry conjugate acid-base theory, an acid is defined as a substance which looses donates protons and thus forming conjugate base and a base is defined as a substance which accepts protons and thus forming conjugate acid.

For the given reaction:

$HF(aq)+NH_3(aq)\rightarrow NH_4^+(aq)+F^-(aq)$

Here $HF$ is loosing a proton, thus it is considered as an acid and after losing a proton, it forms $F^-$ which is a conjugate base.

Similarly ,$NH_3$ is gaining a proton, thus it is considered as an base and after gaining a proton, it forms $NH_4^+$ which is a conjugate acid.