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3 years ago

If a psychologist violates his or her ethical obligations but breaks no laws, the American Psychological Association could

Physics

2 answers:

gogolik [260]3 years ago

8 0

Answer:

C. dismiss them.

Explanation:

The American Psychological Association is a scientific organization and it serves as an umbrella body for the professional psychologists practicing in the United States of America. This professional organization was founded by Granville Stanley Hall in July, 1892 and it has become the largest professional body with over 120,000 members such as scientists, consultants, clinicians, educators etc.

Basically, the American Psychological Association is saddled with the responsibility of providing professional certifications to psychologists and assisting in the advancement of human well-being.

If a psychologist violates his or her ethical obligations but breaks no laws, the American Psychological Association could take action and dismiss or censure them. This is done so as to serve as deterrent to other psychologists and to help maintain the core values, objectives and mission of the professional organization.

tiny-mole [99]3 years ago

3 0

Answer:

Explanation:

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3 years ago

In an oscillating LC circuit, the maximum charge on the capacitor is qm. Determine the charge on the capacitor, q, and the curre

Katarina [22]

Answer:

a. q = qm/√2 b. qm/√(2LC)

Explanation:

a. Charge on the capacitor

Let U₁ = energy in inductor and U₂ = energy in capacitor and U = total energy in circuit.

So, U₁ + U₂ = U.

Since the energy is shared equally between the capacitor and inductor, U₁= U₂,so

2U₂ = U

and U₂ = U/2

Now U₂ = q²/2C where q is the charge on the capacitor with capacitance C and

U = (qm)²/2C where qm is the maximum charge on the capacitor.

Since U₂ = U/2,

Substituting the values for U₂ and U, we have

q²/2C = [(qm)²/2C]/2

q² = (qm)²/2

taking square-root of both sides, we have

q = qm/√2

b. The current in the inductor

Since the energy in the capacitor equals the energy in the inductor,

1/2LI² = 1/2q²/C where L is the inductance of the inductor and I the current through it.

I² = q²/LC

taking square-root of both sides, we have

I = q/√LC

substituting the value of q from above, we have

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3 years ago

What is the total resistance of circuit when resistors connected in series and parallel?

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Explanation:

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