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3 years ago

If a psychologist violates his or her ethical obligations but breaks no laws, the American Psychological Association could

Physics

2 answers:

gogolik [260]3 years ago

8 0

Answer:

C. dismiss them.

Explanation:

The American Psychological Association is a scientific organization and it serves as an umbrella body for the professional psychologists practicing in the United States of America. This professional organization was founded by Granville Stanley Hall in July, 1892 and it has become the largest professional body with over 120,000 members such as scientists, consultants, clinicians, educators etc.

Basically, the American Psychological Association is saddled with the responsibility of providing professional certifications to psychologists and assisting in the advancement of human well-being.

If a psychologist violates his or her ethical obligations but breaks no laws, the American Psychological Association could take action and dismiss or censure them. This is done so as to serve as deterrent to other psychologists and to help maintain the core values, objectives and mission of the professional organization.

tiny-mole [99]3 years ago

3 0

Answer:

Explanation:

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Bumper car A (281 kg) moving +2.82 m/s makes an elastic collision with bumper car B (209 kg) moving -1.72 m/s. What is the veloc

Nuetrik [128]

The velocity of B after elastic collision is 3.45m/s

This type of collision is an elastic collision and we can use a formula to solve this problem.

<h3>Elastic Collision</h3>

$v_2 = \frac{2m_1u_1}{m_1+m_2} - \frac{m_1 - m_2}{m_1 + m_2}u_2$

The data given are;

m1 = 281kg
u1 = 2.82m/s
m2 = 209kg
u2 = -1.72m/s
v1 = ?

Let's substitute the values into the equation.

$v_1 = \frac{2*281*2.82}{281+209} -\frac{281-209}{281+209}(-1.72)\\v_1 = 3.45m/s$

From the calculation above, the final velocity of the car B after elastic collision is 3.45m/s.

Learn more about elastic collision here;

brainly.com/question/7694106

4 0

2 years ago

Andrea and Chuck are riding on a merry-go-round. Andrea rides on a horse at the outer rim of the circular platform, twice as far

marta [7]

a) Their angular speeds are the same

b) Andrea's tangential speed is twice the value of Chuck's tangential speed

Explanation:

The angular speed of Andrea and Chuck is the same.

Let's call $\omega$ the angular speed at which the merry-go-round is rotating. We know that the angular speed is defined as:

$\omega= \frac{2\pi}{T}$

where

$2 \pi$ is the angular displacement covered in one revolution

T is the period of revolution

The merry go round is a rigid body, so all its point cover the same angular displacement in the same time: this means that it doesn't matter where Andrea and Chuck are located along the merry-go-round, their angular speed will still be the same.

For an object in circular motion, the tangential speed is given by

$v=\omega r$

where

$\omega$ is the angular speed

r is the distance from the centre of rotation

Here let's call $r_c$ the distance at which Chuck is rotating, so his tangential speed is

$v_c = \omega r_c$

Now we know that Andrea is rotating twice as far from the centre, so at a distance of

$r_a = 2 r_c$

So his tangential speed is

$v_a = \omega r_a = \omega (2 r_c) = 2(\omega r_c) = 2 v_c$

So, Andrea's tangential speed is twice the value of Chuck's tangential speed.

Learn more about circular motion:

brainly.com/question/2562955

brainly.com/question/6372960

#LearnwithBrainly

5 0

3 years ago

I will be so thankful if u answer correctly!!

polet [3.4K]

Explanation:

The acceleration due to gravity on earth $g_{E}$ is given by

$g_{E} = G\dfrac{M_{E}}{R_{E}^{2}}$

where $G$ = universal gravitational constant

$\:\:\:\:\:\:\:\:\:\:\:\:M_{R}$ = mass of the earth

$\:\:\:\:\:\:\:\:\:\:\:\:R_{E}$ = radius of the earth

Planet Krypton has twice the mass of earth and 3 times the radius so its acceleration due to gravity $g_{K}$ is

$g_{K} = G\dfrac{M_{K}}{R_{K}^{2}}$

$\:\:\:\:\:\: = G\dfrac{(2M_{E})}{(3R_{E})^{2}}$

$\:\:\:\:\;\:= (\dfrac{2}{9})G\dfrac{M_{E}}{R_{E}^{2}}$

$g_{K} = (\dfrac{2}{9})\:g_{E}$

If we multiply both sides by Superman's mass, we get his weights on both planets:

$mg_{K} = (\dfrac{2}{9})\:(mg_{E})$

$W_{K} = (\dfrac{2}{9})\:W_{E} = (\dfrac{2}{9})(900\:N)= 200\:N$

3 0

3 years ago

A complex sound’s quality depends on the mix of harmonics or overtones added to the ______________ frequency

Brilliant_brown [7]

Fundamental frequency is the "base frequency" upon which the sound is built.

4 0

3 years ago

The effect of mechanical work on an object is _. (complete the sentence.)

Advocard [28]

Answer:

Displacement (i.e. change in its final position)

Explanation:

In classical mechanics work is described as the displacement of the body in the direction of the applied force.

<u>Mathematically given as:</u>

$W=F.s\ cos\ \theta$

where:

F = force on the body

s = displacement of the body

θ = angle between the force and direction of displacement

While force, acceleration, velocity can also be the answer for the blank space but the displacement effect is visible during and even after the work has been done, so one can notice the change in position of the object even when the person has not seen the process but just the initial condition of the body.

8 0

3 years ago