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Anton [14]
4 years ago
10

Using a 685 nm wavelength laser, you form the diffraction pattern of a 1.11 mm wide slit on a screen. You measure on the screen

that the 11th dark fringe is 9.85 cm away from the center of the central maximum. How far is the screen located from the slit
Physics
1 answer:
velikii [3]4 years ago
5 0

Answer:

13.8 m

Explanation:

Dark fringes are formed in a single slit experiment due to destructive interference that occurs due to interference.

The position of these dark fringes formed on a screen is given by:

y = \frac{\lambda }{d} (m + 1/2)D

where y = position of  mth minimum

m = order of the minimum

D = distance of the slit from the screen

d = width of the slit

λ = wavelength of the light used

We need to find D:

D = \frac{yd} {\lambda (m + 1/2)} \\

From the question:

m = 11

y = 9.85 cm = 0.0985 m

λ  = 6.83 * 10^{-7} m

d = 1.11 mm = 0.0011 m

Therefore:

D = \frac{0.0985 *0.0011} {6.83 * 10^{-7} *(11 + 1/2)} \\\\D = \frac{0.00010835} {6.83 * 10^{-7}  * (23/2)} \\\\D = 13.8 m

The slit is 13.8 m far from the screen

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Answer:

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3 years ago
No two electrons in an atom can have the same set of four quantum numbers' is
miv72 [106K]

Answer:

D. Pauli's exclusion principle

Explanation:

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I hope you find this information useful and interesting! Good luck!

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4 years ago
Which state of matter has atoms that are spread out and bouncy?
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7 0
3 years ago
Why is accelration negative when velocity is positive.​
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Explanation:

8 0
3 years ago
Imagine that you are working as a roller coaster designer. You want to build a record breaking coaster that goes 70.0 m/s at the
Rzqust [24]

Wow !  This is not simple.  At first, it looks like there's not enough information, because we don't know the mass of the cars.  But I"m pretty sure it turns out that we don't need to know it.

At the top of the first hill, the car's potential energy is

                                  PE = (mass) x (gravity) x (height) .

At the bottom, the car's kinetic energy is

                                 KE = (1/2) (mass) (speed²) .

You said that the car's speed is 70 m/s at the bottom of the hill,
and you also said that 10% of the energy will be lost on the way
down.  So now, here comes the big jump.  Put a comment under
my answer if you don't see where I got this equation:

                                   KE = 0.9  PE

        (1/2) (mass) (70 m/s)² = (0.9) (mass) (gravity) (height)     

Divide each side by (mass): 

               (0.5) (4900 m²/s²) = (0.9) (9.8 m/s²) (height)

(There goes the mass.  As long as the whole thing is 90% efficient,
the solution will be the same for any number of cars, loaded with
any number of passengers.)

Divide each side by (0.9):

               (0.5/0.9) (4900 m²/s²) = (9.8 m/s²) (height)

Divide each side by (9.8 m/s²):

               Height = (5/9)(4900 m²/s²) / (9.8 m/s²)

                          =  (5 x 4900 m²/s²) / (9 x 9.8 m/s²)

                          =  (24,500 / 88.2)  (m²/s²) / (m/s²)

                          =        277-7/9    meters
                                  (about 911 feet)
3 0
3 years ago
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