A is 6:55
B is 37 Minutes
C is 15:12
Step-by-step explanation:
so basically its just adding minutes to a clock, like if its 1:00 o clock and 40 minutes pass it will be 1:40 or if its 12:00 and 25 minutes pass it will be 12:55. There's 60 minutes in an hour so if the time is, let's say, 12:45 and 30 minutes go by itd be 1:15.
C is a little more tricky but thats just because its military time.:) basically instead of going to 12 am to 1 pm it would go from 12:00 AM to 13:00 PM
3x^2-18+5=47
3x^2 = 60
x^2 = 20
x = 4.472 , x = - 4.472
X = x
to solve, subtract both sides by x:
0 = 0
x is always equals to x so infinite solutions
Answer:
20
Step-by-step explanation:
f(x)= x/5
To solve for f(100), we substitute 100 for x everywhere in the equation:
f(100) = (100)/5
f(100) = 20
Answer:
a)0.7
b) 10.03
c) 0.0801
Step-by-step explanation:
Rate of return Probability
9.5 0.1
9.8 0.2
10 0.3
10.2 0.3
10.6 0.1
a.
P(Rate of return is at least 10%)=P(R=10)+P(R=10.2)+P(R=10.6)
P(Rate of return is at least 10%)=0.3+0.3+0.1
P(Rate of return is at least 10%)=0.7
b)
Expected rate of return=E(x)=sum(x*p(x))
Rate of return(x) Probability(p(x)) x*p(x)
9.5 0.1 0.95
9.8 0.2 1.96
10 0.3 3
10.2 0.3 3.06
10.6 0.1 1.06
Expected rate of return=E(x)=sum(x*p(x))
Expected rate of return=0.95+1.96+3+3.06+1.06=10.03
c)
variance of the rate of return=V(x)=![sum(x^2p(x))-[sum(x*p(x))]^2](https://tex.z-dn.net/?f=sum%28x%5E2p%28x%29%29-%5Bsum%28x%2Ap%28x%29%29%5D%5E2)
Rate of return(x) Probability(p(x)) x*p(x) x²*p(x)
9.5 0.1 0.95 9.025
9.8 0.2 1.96 19.208
10 0.3 3 30
10.2 0.3 3.06 31.212
10.6 0.1 1.06 11.236
sum[x²*p(x)]=9.025+19.208+30+31.212+11.236=100.681
variance of the rate of return=V(x)=sum(x²*p(x))-[sum(x*p(x))]²
variance of the rate of return=V(x)=100.681-(10.03)²
variance of the rate of return=V(x)=100.681-100.6009
variance of the rate of return=V(x)=0.0801