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Natali [406]
3 years ago
15

If the second ball has a mass of 2.4kg and a constant acceleration of a⃗ 2= 2.8m/s2 j^ , what must the mass of the first ball be

?

Physics
1 answer:
kompoz [17]3 years ago
8 0
Hope this helps you!

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The primary reason for the path of motion of an object being a smooth curve is: Select an answer and submit. For keyboard naviga
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Answer:

the correct answer is d

Explanation:

The laws of mechanics are related

          F = m a

the acceleration of the body is given by the kinematics

         a = \frac{dv}{dt}

         v = \frac{dx}{dt}

         

substituting

         a = \frac{d2x}{dt^2}

         F = m \frac{d^2x}{dt^2}

Therefore, in order to obtain the force (interaction of a body), continuous curves are needed and derivable from the position and the speed, for which all change in the trajectory of a body must be smooth where smooth is understood to have until the second derived.

Consequently the correct answer is d

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An element with a valence of 8 are most likely noble gases (He, Ne, Ar, etc) which means they're already stable so they dont need to undergo chemical bonds with another atom because they already have a full valence shell.
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What is most likely the amount of energy available at a trophic level of primary consumers if the amount of energy available to
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Answer:

200 kilocalories

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An electric motor draws out 5 A of current from a 20 V battery. How much power is it using?
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Answer:

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The superheroine Xanaxa, who has a mass of 68.1 kg , is pursuing the 75.3 kg archvillain Lexlax. She leaps from the ground to th
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The concept required to solve this problem is associated with potential energy. Recall that potential energy is defined as the product between mass, gravity, and change in height. Mathematically it can be described as

U = mg\Delta h

Here,

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g = Acceleration due to gravity

The change in height will be,

\Delta h = h_f - h_i

The final position of the heroin is below the ground level,

h_f = -16.1m

The initial height will be the zero point of our system of reference,

\Delta h = -16.1m-0m

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Replacing all this values we have,

U = mg\Delta h

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U = -10744.81J

Since the final position of the heroine is located below the ground, there will net loss of gravitational potential energy of 10744.81J

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