Answer: Having Pure Water Is Zero.
Explanation: ...
Question:
A wire 2.80 m in length carries a current of 5.20 A in a region where a uniform magnetic field has a magnitude of 0.430 T. Calculate the magnitude of the magnetic force on the wire assuming the following angles between the magnetic field and the current.
(a)60 (b)90 (c)120
Answer:
(a)5.42 N (b)6.26 N (c)5.42 N
Explanation:
From the question
Length of wire (L) = 2.80 m
Current in wire (I) = 5.20 A
Magnetic field (B) = 0.430 T
Angle are different in each part.
The magnetic force is given by

So from data

Now sub parts
(a)

(b)

(c)

Answer:
The magnitude of the impulse is 1.33 kg m/s
Explanation:
please look at the solution in the attached Word file
Answer:
One would need to know how far apart the towns are:
T = SA / 40 time it takes for first cyclist to travel S1
T = SB / 60 time it takes for cyclist B to travel distance S2
SA + SB = S the distance between the towns
SB = 60 / 40 SA = 1.5 SA
SA + 1.5 SA = S
S = 2.5 SA where cyclist travels distance SA
The time will depend on the separation of the towns.