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3 years ago

What is the main idea of quantum psychics?

1 answer:

6 0

Hello there,
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Quantum mechanics is the body of scientific laws that describe the wacky behavior of photons, electrons and the other particles that make up the universe.
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I hope I was able to help you. :)

[Mark Brainliest] - Correct Certified?

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A beam of protons moves in a circle of radius 0.20 m. The protons move perpendicular to a 0.36-T magnetic field. (a) What is the

gregori [183]

Answer:

a) $v=6.898\times 10^{6}\ m.s^{-1}$ is the speed of each proton

b) $F_c=3.97\times 10^{-13}\ N$

Explanation:

Given:

radius of path of motion, $r=0.2\ m$

we know charge on protons, $q=1.6\times 10^{-19}\ C$

magnetic field strength, $B=0.36\ T$

we've mass of proton, $m=1.67\times 10^{-27}\ kg$

From the equivalence of magnetic force and the centripetal force on the proton:

$F_B=F_C$

$q.v.B=\frac{m.v^2}{r}$

$q.B=\frac{m.v}{r}$

where:

v = speed of the proton

$(1.6\times 10^{-19})\times 0.36=\frac{1.67\times 10^{-27}\times v}{0.2}$

$v=6.898\times 10^{6}\ m.s^{-1}$ is the speed of each proton

Now the centripetal force on each proton:

$F_c=m.\frac{v^2}{r}$

$F_c=1.67\times 10^{-27}\times \frac{(6.898\times 10^6)^2}{0.2}$

$F_c=3.97\times 10^{-13}\ N$

6 0

3 years ago

How many molecules are indicated by writing 2 H2O? A.) 2 B.) 3 C.) 4 D.) 1

Thepotemich [5.8K]

A, 2 molcules
H2O is one molecule, it has 3 atoms (two hydrogen and one oxygen)
2 H2O are two water molecules

7 0

3 years ago

Read 2 more answers

A block of ice(m = 14.0 kg) with an attached rope is at rest on a frictionless surface. You pull the block with a horizontal for

nadezda [96]

Answer:

a) The weight and the normal force of the block has a magnitude of 137.298 newtons and the pull force exerted on the block has a magnitude of 98 newtons.

b) The final speed of the block of ice is 9.8 meters per second.

Explanation:

a) We need to calculate the weight, normal force from the ground to the block and the pull force. By 3rd Newton's Law we know that normal force is the reaction of the weight of the block of ice on a horizontal.

The weight of the block ( $W$ ), measured in newtons, is:

$W = m\cdot g$ (1)

Where:

$m$ - Mass of the block of ice, measured in kilograms.

$g$ - Gravitational acceleration, measured in meters per square second.

If we know that $m = 14\,kg$ and $g = 9.807\,\frac{m}{s^{2}}$ , the magnitudes of the weight and normal force of the block of ice are, respectively:

$N = W = (14\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)$

$N = W = 137.298\,N$

And the pull force is:

$F_{pull} = 98\,N$

The weight and the normal force of the block has a magnitude of 137.298 newtons and the pull force exerted on the block has a magnitude of 98 newtons.

b) Since the block of ice is on a frictionless surface and pull force is parallel to the direction of motion and uniform in time, we can apply the Impact Theorem, which states that:

$m\cdot v_{o} +\Sigma F \cdot \Delta t = m\cdot v_{f}$ (2)

Where:

$v_{o}$ , $v_{f}$ - Initial and final speeds of the block, measured in meters per second.

$\Sigma F$ - Horizontal net force, measured in newtons.

$\Delta t$ - Impact time, measured in seconds.

Now we clear the final speed in (2):

$v_{f} = v_{o}+\frac{\Sigma F\cdot \Delta t}{m}$

If we know that $v_{o} = 0\,\frac{m}{s}$ , $m = 14\,kg$ , $\Sigma F = 98\,N$ and $\Delta t = 1.40\,s$ , then final speed of the ice block is:

$v_{f} = 0\,\frac{m}{s}+\frac{(98\,N)\cdot (1.40\,s)}{14\,kg}$

$v_{f} = 9.8\,\frac{m}{s}$

The final speed of the block of ice is 9.8 meters per second.

6 0

2 years ago

2 Points

yulyashka [42]

The force applied to lift the crate is 171 N

Explanation:

The lever works on the principle of equilibrium of moments, so we can write:

$F_i d_i = F_o d_o$

where

$F_i$ is the force in input

$d_i$ is the arm of the input force

$F_o$ is the output force

$d_o$ is the arm of the output force

For the lever in this problem, we have:

$d_i = 0.25 m$

$d_o = 0.19 m$

$F_i = 130 N$ (force applied)

Solving the equation for $F_o$ , we find the force applied to lift the crate:

$F_o = \frac{F_i d_i}{d_o}=\frac{(130)(0.25)}{0.19}=171 N$

Learn more about levers:

brainly.com/question/5352966

#LearnwithBrainly

6 0

3 years ago

A reversible Carnot engine has an efficiency of 30% and it operates between a heat source maintained at T 1 , and a refrigerator

bixtya [17]

To solve this problem we will apply the concepts related to the thermal efficiency given in an engine of the Carnot cycle. Here we know that efficiency is given under the equation

$\eta = 1 - \frac{T_2}{T_1}$