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Vikki [24]
3 years ago
11

Match the organelles to their functions.

Chemistry
2 answers:
katovenus [111]3 years ago
8 0

Answer:

1. Golgi apparatus- 2. produces lysosomes

2. Lysosome- 3. digests foreign material

3. Smooth endoplasmic reticulum- 1. produces lipids and fats

4. nucleus- 4. command other organelles

1. Golgi apparatus- 2. produces lysosomes

The proteins are synthesized in a rough endoplasmic reticulum. These proteins are packed in a vesicle and send to the golgi apparatus. The proteins and others cellular components not required by the cell are packed by golgi apparatus in a vesicle or number of vesicles also consisting of digestive enzymes. These vesicles are called as lysosomes. 2. Lysosome- 3. digests foreign material

Lysosomes are the organelles found in animal cell, they contain digestive enzymes like acid hydrolases. The enzymes facilitates the digestion of organelles, foreign agents like viruses and bacteria, food particles and other cellular wastes.

3. Smooth endoplasmic reticulum- 1. produces lipids and fats

Smooth endoplasmic reticulum is a meshwork of tubes it is attached with the periphery of the cell. The main function of the endoplasmic reticulum is the synthesis and storage of lipids like phospholipids, cholesterol and fats.

4. nucleus- 4. command other organelles

The nucleus is the command center of the cell. It contains the hereditary information of the cell in the form of genetic material. The genetic material is the form of genes, which when express result in the synthesis of proteins by the cell organelles like ribosomes, rough endoplasmic reticulum.

DaniilM [7]3 years ago
3 0
Golgi Apparatus-produces lysosomes

Lysosomes-digest foreign material

Smooth Endoplasmic Reticulum-produces lipids and fats

Nucleus-commands other organelles
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Mercury’s atomic emission spectrum is shown below. Estimate the wavelength of the orange line. What is its frequency? What is th
lions [1.4K]

The wavelength of the orange line is 610 nm, the frequency of this emission is 4.92 x 10¹⁴ Hz and the energy of the emitted photon corresponding to this <em>orange line</em> is 3.26 x 10⁻¹⁹ J.

<em>"Your question is not complete, it seems to be missing the diagram of the emission spectrum"</em>

the diagram of the emission spectrum has been added.

<em>From the given</em><em> chart;</em>

The wavelength of the atomic emission corresponding to the orange line is 610 nm = 610 x 10⁻⁹ m

The frequency of this emission is calculated as follows;

c = fλ

where;

  • <em>c is the speed of light = 3 x 10⁸ m/s</em>
  • <em>f is the frequency of the wave</em>
  • <em>λ is the wavelength</em>

f = \frac{c}{\lambda } \\\\f = \frac{3\times 10^8}{610 \times 10^{-9}} \\\\f = 4.92 \times 10^{14} \ Hz

The energy of the emitted photon corresponding to the orange line is calculated as follows;

E = hf

where;

  • <em>h is Planck's constant = 6.626 x 10⁻³⁴ Js</em>

<em />

E = (6.626 x 10⁻³⁴) x (4.92 x 10¹⁴)

E = 3.26 x 10⁻¹⁹ J.

Thus, the wavelength of the orange line is 610 nm, the frequency of this emission is 4.92 x 10¹⁴ Hz and the energy of the emitted photon corresponding to this <em>orange line</em> is 3.26 x 10⁻¹⁹ J.

Learn more here:brainly.com/question/15962928

6 0
2 years ago
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