Answer:
there are three Fluorine atom. This is because Nitrogen give 3 electron away but fluorine can only take 1. So nitrogen gives 1 neutron to 3 fluorine each which makes it a stable compound
Answer:
Please see the attachments
Explanation:
Please see the attachments below structures of the 3 isomers of C8H18 that contain 3 methyl branches on the main chain, 2 of which are on the same carbon.
1.56 moles of N2 are needed to fill a 35 L tank at standard temperature and pressure. Details about moles can be found below.
<h3>How to calculate number of moles?</h3>
The number of moles of a substance can be calculated using the following formula:
PV = nRT
Where;
- P = pressure
- V = volume
- n = number of moles
- R = gas law constant
- T = temperature
At STP;
- T = 273K
- P = 1 atm
- R = 0.0821 Latm/molK
1 × 35 = n × 0.0821 × 273
35 = 22.41n
n = 35/22.41
n = 1.56mol
Therefore, 1.56 moles of N2 are needed to fill a 35 L tank at standard temperature and pressure.
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Answer:
option d
Explanation:
Molecular sizes of gaseous molecules are very less. Volume occupied by the all the molecules of the gases are very less or negligible as compared to the container in which it is kept. Therefore, most of the volume occupied by gaseous molecules are negligible.
Volume occupied by the gaseous molecules are actually the volume of the container and its does not depend upon the amount, molecular mass or dipole moment of the gaseous molecules.
Therefore, the correct option is d ‘Because most of the volume occupied by the substance is empty space.’
Answer: 50.7 grams
Explanation:
To calculate the moles, we use the equation:
a) moles of 
![\text{Number of moles}=molarity\times {\text {Volume in L]}=0.417M\times 0.528L=0.220moles](https://tex.z-dn.net/?f=%5Ctext%7BNumber%20of%20moles%7D%3Dmolarity%5Ctimes%20%7B%5Ctext%20%7BVolume%20in%20L%5D%7D%3D0.417M%5Ctimes%200.528L%3D0.220moles)
The balanced chemical equation is:
is the limiting reagent as it limits the formation of product and 
is in excess.
According to stoichiometry :
2 moles of give = 1 mole of 
Thus 0.220 moles of give=
of
Mass of 
Thus 50.7 g of will be formed.
