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ludmilkaskok [199]
3 years ago
15

Help me please!! thanks!

Chemistry
1 answer:
Alona [7]3 years ago
4 0

Answer:

i took a picture of my answer. hope its right

Explanation:

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What is the compound of scI2
klemol [59]

Answer:

sulfur dichloride

Explanation:

SCl2 is the chemical formula for sulfur dichloride. This compound is made of only two elements, so it is a binary compound.

4 0
3 years ago
26 POINTS AND BRAINLY
Mandarinka [93]
C. The answer is c.
4 0
3 years ago
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Calculate the pH of each solution at 25∘C
JulijaS [17]

Answer: pH of HCl =5, HNO3 = 1,

NaOH = 9, KOH = 12

Explanation:

pH = -log [H+ ]

1. 1.0 x 10^-5 M HCl

pH = - log (1.0 x 10^-5)

= 5 - log 1 = 5

2. 0.1 M HNO3

pH = - log (1.0 x 10 ^ -1)

pH = 1 - log 1 = 1

3. 1.0 x 10^-5 NaOH

pOH = - log (1.0 x 10^-5)

pOH = 5 - log 1 = 5

pH + pOH = 14

Therefore , pH = 14 - 5 = 9

4. 0.01 M KOH

pOH = - log ( 1.0 x 10^ -2)

= 2 - log 1 = 2

pH + pOH = 14

Therefore, pH = 14 - 2 = 12

8 0
3 years ago
The cycle repeats when the carbon stored in the atmosphere as carbon dioxide gas is taken in.
Rzqust [24]

Answer:

Order of the cycle:

Step -1>>>>Step -4 >>>> Step -3 >>>>> step -2.

Explanation:

<u>Step -1:</u>

Carbon dioxide is taken in by plants during photosynthesis.

<u>Step -4;</u>

The animal eats a plant and uses its carbohydrates for energy.

<u>Step - 3</u>

The animal releases the carbon dioxide back into the atmosphere during respiration.

<u>Step -2</u>

The cycle repeats when the carbon stored in the atmosphere as carbon dioxide gas is taken in.

Therefore, order of the cycle is Step -1>>>>Step -4 >>>> Step -3 >>>>> step -2.

5 0
3 years ago
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An excess of Ba(No3)2 reacts with 250ml of H2SO4 solution to give 0.55g of BaSo4.determine The concentration in moles per litre
Wewaii [24]
Chemical reaction: Ba(NO₃)₂ + H₂SO₄ → BaSO₄ + 2HNO₃.
V(H₂SO₄) = 250 mL ÷ 1000 mL/L = 0,25 L.
m(BaSO₄) = 0,55 g.
n(BaSO₄) = m(BaSO₄) ÷ M(BaSO₄).
n(BaSO₄) = 0,55 g ÷ 233,38 g/mol.
n(BaSO₄) = 0,00235 mol.
From chemical reaction: n(BaSO₄) : n(Ba(NO₃)₂) = 1 : 1.
n(Ba(NO₃)₂) = 0,00235 mol.
c(Ba(NO₃)₂) = n(Ba(NO₃)₂) ÷ V.
c(Ba(NO₃)₂) = 0,00235 mol ÷ 0,25 L.
c(Ba(NO₃)₂) = 0,0095 mol/L.
7 0
3 years ago
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