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3 years ago

There's more to motion than simply changing position. True Or False

Physics

2 answers:

prohojiy [21]3 years ago

8 0

Answer: I think that it is False, if its wrong I am sorry.

Explanation:

AleksandrR [38]3 years ago

5 0

True, there is friction, the energy needed to move the object, and the weight of the said object.

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Which lists three organic biological molecules?

Nat2105 [25]

Answer:

carbohydrates , minerals - lime coal

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3 years ago

A spectroscope creates a spectrum, or array of colors, based on the light emitted by a star. How are

Ivanshal [37]

In a spectrograph, black lines can be seen going through the array of colors. The pattern of these lines indicate the composition of the star.

Different elements block different parts of the spectrum, resulting in black lines.

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3 years ago

A cylindrical block of mass M=50kg and height h=0.2m is hanging on a rope and is in equilibrium. Any difference in atmospheric p

agasfer [191]

Answer:

$\Delta P = 1961.4\,Pa$

Explanation:

The difference of pressure is given by gauge pressure:

$\Delta P = \rho_{w}\cdot g \cdot \Delta h$

$\Delta P = \left(1000\,\frac{kg}{m^{3}} \right)\cdot \left(9.807\,\frac{m}{s^{2}} \right)\cdot (0.2\,m)$

$\Delta P = 1961.4\,Pa$

8 0

4 years ago

Read 2 more answers

17 of 24 Constants In an experiment to simulate conditions within an automobile engine, 0.165 mol of air at a temperature of 700

steposvetlana [31]

Answer:

a. T₂ = 901.43 ° K

b. T₂ = 843.85 ° K

Explanation:

Given

η = 0.165 mol , Q = 690 J , V = 280 cm³ , P = 3.40 x 10 ⁶ Pa , T₁ = 700 ° K

Using the equation that describe the experiment of heat

Q = η * Cv * ΔT

Nitrogen Cv = 20.76 J / mol ° K

ΔT = T₂ - T₁

T₂ = [ Q / ( η * Cv) ] + T₁

T₂ = [ 690 J / ( 0.165 mol * 20.76 J / mol ° K ) ] + 700 ° K

T₂ = 901.43 ° K

Nitrogen Cp = 29.07 J / mol ° K

T₂ = [ Q / ( η * Cv) ] + T₁

T₂ = [ 690 J / ( 0.165 mol * 29.07 J / mol ° K ) ] + 700 ° K

T₂ = 843.85 ° K

5 0

3 years ago

A hot-air balloon of diameter 12 mm rises vertically at a constant speed of 15 m/sm/s. A passenger accidentally drops his camera

jeka94

To solve this problem we will apply the linear motion kinematic equations. With the information provided we will calculate the time it takes for the object to fall. From that time, considering that the ascent rate is constant, we will take the reference distance and calculate the distance traveled while the object hit the ground, that is,

$h = v_0 t -\frac{1}{2} gt^2$