Work done against gravity to climb upwards is always stored in the form of gravitational potential energy
so we can say
here h = vertical height raised
so here we know that
here we have
now from above equation
so work done will be given by above value
Answer:
The speed of the vehicles immediately after the collision is 5.84 m/s.
Explanation:
The speed of the vehicles after the collision can be found by conservation of linear momentum:
Where:
m₁: is the mass of the car = 0.5 ton = 500 kg
m₂: is the mass of the lorry = 9.5 ton = 9500 kg
: is the initial speed of the car = 40 km/h = 11.11 m/s
: is the initial speed of the lorry = 20 km/h = 5.56 m/s
: is the final speed of the car =?
: is the final speed of the lorry =?
Since the two vehicles become tightly locked together after the collision =
:
Therefore, the speed of the vehicles immediately after the collision is 5.84 m/s.
I hope it helps you!
Answer:
The altitude of the plane is 379.5 m.
Explanation:
Initial horizontal velocity, u = 59.1 m/s
Horizontal distance, d = 521 m
let the time taken by the packet to cover the distance is t.
Horizontal distance = horizontal velocity x time
521 = 59.1 x t
t = 8.8 s
let the vertical height is h .
Use second equation of motion in vertical direction.