Answer: 3.84dB
Explanation:
Since person A is talking 1.2dB louder than B, we will have
A = 1.2B... (1)
Similarly, person C is talking 3.2 dB louder than person A, we have
C = 3.2A... (2)
From equation 1, B = A/1.2... (3)
To get the ratio of the sound intensity of person C to the sound intensity of person B, we will divide equation 2 by 3 to give
C/B = 3.2A/{A/1.2}
C/B = 3.2A×1.2/A
C/B = 3.2×1.2
C/B = 3.84dB
Answer:
if your glasses are polarized, you can see the fish in the water. also im pretty sure its d
Explanation:
Answer:
The electric field is
and the ditection is from outer to inner side of the membrane.
Explanation:
We know the electric field (
) is given by
, 'V' being the potential.
In 1-D, it can be written as
![E=\dfrac{V}{d}](https://tex.z-dn.net/?f=E%3D%5Cdfrac%7BV%7D%7Bd%7D)
where 'd' is the separation of space in between the potential difference is created.
Given,
and the thickness of the cell membrane is
.
Therefore the created electric field through the cell membrane is
![E = \dfrac{0.07~V}{8 \times 10^{-9}~m} = 8.75 \times 10^{6}~m~s^{-1}](https://tex.z-dn.net/?f=E%20%3D%20%5Cdfrac%7B0.07~V%7D%7B8%20%5Ctimes%2010%5E%7B-9%7D~m%7D%20%3D%208.75%20%5Ctimes%2010%5E%7B6%7D~m~s%5E%7B-1%7D)
Answer:
The value of tension on the cable T = 1065.6 N
Explanation:
Mass = 888 kg
Initial velocity ( u )= 0.8 ![\frac{m}{sec}](https://tex.z-dn.net/?f=%5Cfrac%7Bm%7D%7Bsec%7D)
Final velocity ( V ) = 0
Distance traveled before come to rest = 0.2667 m
Now use third law of motion
=
- 2 a s
Put all the values in above formula we get,
⇒ 0 =
- 2 × a ×0.2667
⇒ a = 1.2 ![\frac{m}{sec^{2} }](https://tex.z-dn.net/?f=%5Cfrac%7Bm%7D%7Bsec%5E%7B2%7D%20%7D)
This is the deceleration of the box.
Tension in the cable is given by T = F = m × a
Put all the values in above formula we get,
T = 888 × 1.2
T = 1065.6 N
This is the value of tension on the cable.
Answer:
ρ = 7500 kg/m³
Explanation:
Given that
mass ,m = 12 kg
Displace volume ,V= 1.6 L
We know that
1000 m ³ = 1 L
Therefore V= 0.0016 m ³
When metal piece is fully submerged
We know that
mass = Density x volume
![m=\rho \times V](https://tex.z-dn.net/?f=m%3D%5Crho%20%5Ctimes%20V)
Now by putting the values in the above equation
![\rho=\dfrac{12}{0.0016}\ kg/m^3](https://tex.z-dn.net/?f=%5Crho%3D%5Cdfrac%7B12%7D%7B0.0016%7D%5C%20kg%2Fm%5E3)
ρ = 7500 kg/m³
Therefore the density of the metal piece will be 7500 kg/m³.