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3 years ago

8

A basketball player standing under the hoop shoots the ball straight up with an initial velocity of v0Part (a) What is the maxim

um height, h (in meters), above the launch point the basketball will achieve?

1 answer:

Mama L [17]3 years ago

6 0

Answer:

Maximum height will be $h=\sqrt{\frac{v_0^2}{2g}}$

Explanation:

We have given initial velocity through which basketball is thrown $=v_0$

Acceleration due to gravity $=g\ m/sec^2$

At maximum height velocity will be zero

So final velocity v = 0 m /sec

According to third equation of motion $v^2=u^2+2gh$

$0^2=v_0^2-2gh$ ( Negative sign is due to upward acceleration )

$h=\sqrt{\frac{v_0^2}{2g}}$

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Neporo4naja [7]

Answer:

Explanation:

Let the charge on proton be q .

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= V₀ q

Due to gain of energy , its kinetic energy becomes 1/2 m v₀²

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V₀ q = 1/2 m v₀²

In the second case , gain of energy in electrical field

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3 years ago

To test the performance of its tires, a car

velikii [3]

<u>Answer</u>:

The coefficient of static friction between the tires and the road is 1.987

<u>Explanation</u>:

<u>Given</u>:

Radius of the track, r = 516 m

Tangential Acceleration $a_r$ = 3.89 m/s^2

Speed,v = 32.8 m/s

<u>To Find:</u>

The coefficient of static friction between the tires and the road = ?

<u>Solution</u>:

The radial Acceleration is given by,

$a_{R = \frac{v^2}{r}$

$a_{R = \frac{(32.8)^2}{516}$

$a_{R = \frac{(1075.84)}{516}$

$a_{R = 2.085 m/s^2$

Now the total acceleration is

$\text{ total acceleration} = \sqrt{\text{(tangential acceleration)}^2 +{\text{(Radial acceleration)}^2$

=> $= \sqrt{ (a_r)^2+(a_R)^2}$

=> $\sqrt{ (3.89 )^2+( 2.085)^2}$

=> $\sqrt{ (15.1321)+(4.347)^2}$

=> $19.4791 m/s^2$

The frictional force on the car will be f = ma------------(1)

And the force due to gravity is W = mg--------------------(2)

Now the coefficient of static friction is

$\mu =\frac{f}{W}$

From (1) and (2)

$\mu =\frac{ma}{mg}$

$\mu =\frac{a}{g}$

Substituting the values, we get

$\mu =\frac{19.4791}{9.8}$

$\mu =1.987$

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Troposphere, stratosphere, mesosphere, thermosphere, exosphere

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Which form of energy does the motor convert most of its electric energy into?

aev [14]

Answer:

Kinetic energy

Explanation:

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A state patrol officer saw a car start from rest at a highway on-ramp. She radioed ahead to another officer 20 mi along the hig

Vikentia [17]

Answer:

We know from the basic speed distance relation that

$Speed=\frac{Distance}{Time}$

Since the car started from rest and it covered the distance between the 2 officer's in 19 minutes we have speed of the car

$Speed=\frac{Distance}{Time}\\\\Speed=\frac{20}{\frac{19}{60}}=63.16mph$

Which clearly exceeds the limit of $60\frac{mi}{hr}$

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3 years ago