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Rudiy27
3 years ago
9

What volume of 7.25 mol/L stock solution in needed to make 3.84 L of 8.50 mol/L solution?

Chemistry
1 answer:
Serjik [45]3 years ago
7 0

Answer:

4.50 L

Explanation:

First we <u>calculate how many moles are there in 3.84 L of a 8.50 mol/L solution</u>:

  • 3.84 L * 8.50 mol/L = 32.64 mol

Now, keeping in mind that

  • Concentration = Mol / Volume

we can calculate the volume of a 7.25 mol/L solution that would contain 32.64 moles:

  • Volume = Mol / Concentration
  • Volume = 32.64 mol ÷ 7.25 mol/L
  • Volume = 4.50 L

So we could take 4.50 L of the 7.25 mol/L solution and evaporate the solvent until only 3.84 L remain.

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Answer:

B

Explanation:

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...which isn't actually an option because none of them have decimal points but I would say it is B anyway because it is the equivalent ratio and maybe there was a typo.

Hope this helped!

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Answer:

10 moles of SO₂ are produced when 5 moles of FeS₂

Explanation:

Stoichiometry: it is the theoretical proportion in which the chemical species are combined in a chemical reaction. The stoichiometric equation of a chemical reaction relates molecules or number of moles of all the reagents and products that participate in the  reaction.

In other words, stoichiometry establishes relationships between the molecules or elements that make up the reactants of a chemical equation with the products of said reaction. The relationships established are molar relationships (that is, moles) between the compounds or elements that make up the chemical equation.

The stoichiometric coefficients of a chemical reaction indicate the proportion in which said substances react.

Taking into account the above, you can apply the following rule of three: by stoichiometry if 4 moles of FeS₂ produce 8 moles of SO₂, then when reacting 5 moles of FeS₂ how many moles of SO₂ will they produce?

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moles of SO₂= 10

<u><em>10 moles of SO₂ are produced when 5 moles of FeS₂</em></u>

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