Answer:
42.6 % CHCl₃, 13.83 % C₃H₆O and 43.5 % CH₃COBr
Explanation:
This is a solution with 3 compounds:
96.2 g of CHCl₃
31.2 g of C₃H₆O
98.1 g of CH₃COBr
Total mass of solution is : 96.2g + 31.2 g + 98.1g = 225.5 g
Percent by mass is, the mass of the compounds in 100 g of solution
Let's prepare the rule of three
225.5 g of solution have ____ 96.2 g ___ 31.2 g _____98.1 g
100 g of solution would have ____
(100 . 96.2) / 225.5 = 42.6
(100 . 31.2) / 225.5 = 13.83
(100 . 98.1) / 225.5 = 43.5
Answer:
103.3 g
Explanation:
Data Given:
Volume of carbon tetrachloride (v) = 65.0 mL
Density of carbon tetrachloride (d) = 1.59 g/cm³
Solution:
Convert volume of carbon tetrachloride from ml to cm³
1 ml = 1 cm³
so,
65.0 mL = 65.0 cm³
Formula used to calculated mass of carbon tetrachloride should be taken for experiment.
d = m/v
Rearrange the above equation:
m = d x v . . . . . . .(1)
Put values in equation 1
m = 1.59 g/cm³ x 65.0 cm³
m = 103.3 g
Number of electrons or protons <<<====
