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Answer:
22.77 g.
he limiting reactant is O₂, and the excess reactant is Mg.
Explanation:
- From the balanced reaction:
<em>Mg + 1/2O₂ → MgO,</em>
1.0 mole of Mg reacts with 0.5 mole of oxygen to produce 1.0 mole of MgO.
- We need to calculate the no. of moles of (16.3 g) of Mg and (4.52 g) of oxygen:
no. of moles of Mg = mass/molar mass = (16.3 g)/(24.3 g/mol) = 0.6708 mol.
no. of moles of O₂ = mass/molar mass = (4.52 g)/(16.0 g/mol) = 0.2825 mol.
So. 0.565 mol of Mg reacts completely with (0.2825 mol) of O₂.
<em>∴ The limiting reactant is O₂, and the excess reactant is Mg (0.6708 - 0.565 = 0.1058 mol).</em>
<u><em>Using cross multiplication:</em></u>
1.0 mole of Mg produce → 1.0 mol of MgO.
∴ 0.565 mol of Mg produce → <em>0.565 mol of MgO.</em>
<em>∴ The amount of MgO produced = no. of moles x molar mass </em>= (0.565 mol)(40.3 g/mol) = <em>22.77 g.</em>
Answer:In a chemistry experiment, 10g of urea, NH2CONH2 (s), is dissolved in 150 mL of water in a simple calorimeter. A temperature decrease of 3.7oC is measured. Calculate the molar enthalpy of solution (∆Hs). ... an ideal gas B if 0.622 g sample of gas B occupies a volume of 300 mL at 35 °C and 1.038 atm.
Explanation:
Answer
The matching is numbered and represented in red arrowsi n the diagram below:
Explanation
In a steam turbine electricity generation, the mechanical energy in form of pressure present in steam is extracted and converted into kinetic energy by allowing the steam to flow through the stationary blades. This kinetic energy is transmitted to the moving blades connected to the alternator of a steam turbine generator.
The matching of the process is shown below:
