Answer: Theoretical mass of sodium sulphate ( 
) is 514.118 grams.
Explanation: For a given reaction,
As NaOH is used in excess, therefore it is an excess reagent and 
is a limiting reagent as the quantity of the product will depend on it.
We are given 355 grams of .
Molar mass of = 98.079 g/mol
Molar mass of = 142.04 g/mol
1 mole of is producing 1 mole of , so
98.079 g/mol of will produce 142.04 g/mol of
355 grams of will produce = 
of
Mass of = 514.118 grams
Answer:
The standard change in free energy for the reaction = - 437.5 kj/mole
Explanation:
The standard change in free energy for the reaction:
4 KClO₃ (s) → 3 KClO₄(s) + KCl(s)
Given that ΔGf(KClO3(s)) = -290.9 kJ/mol;
ΔGf(KClO4(s)) = -300.4 kJ/mol;
ΔGf(KCl(s)) = -409 kJ/mol
According to Hess's law
ΔGr (Free energy change of reaction)= ∑(Product free energy - reactant free energy)
⇒ ΔGr⁰ = {3 x (-300.4) + (-409)} - {3 x (- 290.9)}
= - 901.2 - 409 + 872.7
= - 437.5 kj/mole
Yo sup??
since A has a hydroxyl group ie OH therefore it's an alcohol
and since B has an oxygen between two carbons therefore it's an ether.
hence the correct answer is option B
A is alcohol and B is ether
Hope this helps
Answer:
D)The sound quality for these waves cannot be compared.
Explanation:
I've done it on e2020
<u>Answer:</u> The volume of barium chlorate is 195.65 mL
<u>Explanation:</u>
To calculate the volume of solution, we use the equation used to calculate the molarity of solution:
Given mass of barium chlorate = 25.0 g
Molar mass of barium chlorate = 304.23 g/mol
Molarity of solution = 0.420 mol/L
Volume of solution = ?
Putting values in above equation, we get:
Hence, the volume of barium chlorate is 195.65 mL
