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Sedbober [7]
3 years ago
10

Given the balanced equation representing a reaction:

Chemistry
1 answer:
lapo4ka [179]3 years ago
8 0
The answer is (3) 112 g. The question gives the balanced reaction and specific that 88 grams of CO2 has completely reacted and produces 200 grams of CaCO3. So the mass of CaO equals 200-88=112 g.
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According to Newton's Third Law, If one object exerts a force on a second object, the second object exerts a force on the first
blagie [28]

Equal in magnitude and opposite in direction.

3 0
2 years ago
100 POINTS!!! WILL GIVE BRAINLIEST FOR DETAILED AND CORRECT ANSWER!!!
sveticcg [70]

Answer:

dissolve rocksalt in heated water

Explanation:

If the rock salt is one large chunk, grind it into a powder using a mortar and pestle or a coffee grinder.

Add 30-50 milliliters of water to six heaping spatula scoops of rock salt.

Stir to dissolve the salt.

Place the filter paper in the mouth of the funnel.

Place the evaporating dish under the funnel to collect the liquid.

Slowly pour the rock salt solution into the funnel. Make sure you don't over-fill the funnel. You don't want the liquid to flow around the top of the filter paper because then it isn't getting filtered.

Save the liquid (filtrate) that comes through the filter. Many of the mineral contaminants did not dissolve in the water and were left behind on the filter paper.

Place the evaporating dish containing the filtrate on the tripod.

Position the Bunsen burner under the tripod.

Slowly and carefully heat the evaporating dish. Be careful! If you apply too much heat, you might break the dish.

Gently heat the filtrate until all the water is gone. It's okay if the salt crystals hiss and move a little.

Turn off the burner and collect your salt. Although some impurities will remain in the materials, many of them will have been removed simply by using the difference in solubility in water, mechanical filtration, and by applying heat to drive off volatile compounds.

If you want to further purify the salt, you can dissolve your product in hot water and crystallize the sodium chloride from it.

6 0
3 years ago
What is the molecular formula of the hydrocarbon whose molar mass is 536 g/mol and contains 89.55 w/w% carbon?
leonid [27]

Given the percentage composition of HC as C → 81.82 % and H → 18.18 %

So the ratio of number if atoms of C and H in its molecule can will be:

C : H = 81.82 12 : 18.18 1 C : H = 6.82 : 18.18 = 6.82 6.82 : 18.18 6.82 = 1 : 2.66 ≈ 3 : 8

So the Empirical Formula of hydrocarbon is:

C 3 H 8

As the mass of one litre of hydrocarbon is same as that of C O 2 The molar mass of the HC will be same as that of C O 2 i.e 44 g mol

Now let Molecular formula of the HC be ( C 3 H 8 ) n

Using molar mass of C and H the molar mass of the HC from its molecular formula is:

( 3 × 12 + 8 × 1 ) n = 44 n So 44 n = 44 ⇒ n = 1

Hence the molecular formula of HC is C 3 H 8

Does that help?

7 0
3 years ago
The concentration of reactants and products and the rate of reaction were measured during a chemical reaction. After the first 3
igomit [66]

Answer: B

Explanation:

4 0
2 years ago
Calculate the standard reaction enthalpy for the reaction NO2(g) → NO(g) + O(g) given +142.7 kJ/mol for the standard enthalpy of
bulgar [2K]

Answer:

The standard reaction enthalpy for the given reaction is 235.15 kJ/mol.

Explanation:

O_2(g) \rightarrow \frac{2}{3}O_3(g),\Delta H^o_{1}=142.7 kJ/mol..[1]

O_2(g) \rightarrow 2 O(g),\Delta H^o_{2}=498.4 kJ/mol..[2]

NO(g) + O_3(g)\rightarrow NO_2(g) + O_2(g) ,\Delta H^o_{3} = -200 kJ/mol..[3]

NO_2(g)\rightarrow NO(g) + O(g),\Delta H^o_{4}=?..[4]

Using Hess's law:

Hess’s law of constant heat summation states that the amount of heat absorbed or evolved in a given chemical equation remains the same whether the process occurs in one step or several steps.

2 × [4] = [2]- (3 ) × [1] - (2) × [3]

2\times \Delta H^o_{4}=\Delta H^o_{2} -3\times \Delta H^o_{1}-2\times \Delta H^o_{3}

2\times \Delta H^o_{4}=498.4 kJ/mol-3\times 142.7 kJ/mol-2\times -200 kJ/mol

2\times \Delta H^o_{4}=470.3 kJ/mol

\Delta H^o_{4}=\frac{470.3 kJ/mol}{2}=235.15 kJ/mol

The standard reaction enthalpy for the given reaction is 235.15 kJ/mol.

7 0
3 years ago
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