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3 years ago

Relationship between galactose and mannose

Chemistry

2 answers:

BartSMP [9]3 years ago

6 0

Answer:

Mannose is a simple sugar or monosaccharide that is found as part of some polysaccharides in plants and in some animal glycoproteins. Galactose is converted to glucose in the liver to serve as fuel for cells in the body.

Explanation:

Harman [31]3 years ago

6 0

Mannose is a sugar monomer of the aldohexose series of carbohydrates.

A galactose molecule linked with a glucose molecule forms a lactose molecule.

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Processes that increase the density of seawater include evaporation and _____.

Elena L [17]

Correct Answer: option C: Formation of sea ice

Reason:
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3 years ago

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How many seconds does it take a race horse to run six furlongs at 40.7 miles per hour if: I furlong = 40 rods; 5.5 yards = 1 rod

lana [24]

Distance traveled by the race horse=6 furlongs

Converting the distance from furlongs to rods: 40 rods =1 furlong

$6 furlongs*\frac{40rods}{1furlong} =240rods$

Converting the distance from rods to yards, feet and miles: 5.5 yards = 1 rod, 3foot =1 yard, 1 mile = 5280 feet.

$240rods*\frac{5.5yards}{1rod}*\frac{3foot}{1yard}*\frac{1mi}{5280feet}=0.75mi$

The given speed of race horse = 40.7mi/hr

Calculating the time required:

$0.75mi*\frac{1hr}{40.7mi}*\frac{60min}{1hr}*\frac{60s}{1min}= 66.34s$

Therefore, 66.34 s is required for a race horse to run six furlongs at 40.7 miles per hour.

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3 years ago

During the experiment a student precipitated and digested the BaSO4. After allowing the precipitate to settle, they added a few

OlgaM077 [116]

Answer:

Incomplete precipitation of barium sulfate

Explanation:

The student has precipitated and digested the barium sulfate on his/her side. But on the addition of $BaCl_2$ in the solution, the solution become cloudy. This happened because incomplete precipitation of barium sulfate by the student. When $BaCl_2$ is added, there are still sulfate ions present in the solution with combines with $BaCl_2$ and forms $BaSO_4$ and the formation of this precipitate makes the solution cloudy.

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3 years ago

How many grams of NO can be produced if 204 g of NO2 is mixed with 58.1 g of H2O?

Goshia [24]

Answer:

44.4 grams of NO can be produced

Explanation:

Step 1: Data given

Mass of NO2 = 204 grams

Molar mass NO2 = 46.0 g/mol

Mass of H2O = 58.1 grams

Molar mass H2O = 18.02 g/mol

Step 2: The balanced equation

3NO2 + H2O→ 2HNO3 + NO

Step 3: Calculate moles NO2

Moles NO2 = 204 grams / 46.0 g/mol

Moles NO2 = 4.43 moles

Step 4: Calculate moles H2O

Moles H2O = 58.1 grams / 18.02 g/mol

Moles H2O = 3.22 moles

Step 5: Calculate limiting reactant

For 3 moles NO2 we need 1 mol H2O to produce 2 moles HNO3 and 1 mol NO

NO2 is the limiting reactant. It will completely be consumed (4.43 moles). H2O is in excess. there will react 4.43 /3 = 1.48 moles. There will remain 3.22 - 1.48 = 1.74 moles

Step 6: Calculate moles NO

For 3 moles NO2 we need 1 mol H2O to produce 2 moles HNO3 and 1 mol NO

For 4.43 moles NO2 we'll have 4.43/3 = 1.48 moles NO

Step 7: Calculate mass NO

Mass NO = 1.48 moles * 30.01 g/mol

Mass NO = 44.4 grams

44.4 grams of NO can be produced

3 0

3 years ago

Please help with this questionz. ....plz<br>plzzzzz

anygoal [31]

Answer:

baby which question you want to answer me

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2 years ago

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Relationship between galactose and mannose​

Relationship between galactose and mannose