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notka56 [123]
3 years ago
6

Relationship between galactose and mannose​

Chemistry
2 answers:
BartSMP [9]3 years ago
6 0

Answer:

Mannose is a simple sugar or monosaccharide that is found as part of some polysaccharides in plants and in some animal glycoproteins. Galactose is converted to glucose in the liver to serve as fuel for cells in the body.

Explanation:

Harman [31]3 years ago
6 0

Mannose is a sugar monomer of the aldohexose series of carbohydrates.

A galactose molecule linked with a glucose molecule forms a lactose molecule.

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When a bunsen burner is properly adjusted, what should the flame look like?.
DochEvi [55]

When a bunsen burner is properly adjusted, the flame look like outer violet and inner blue colour.

<h3>What is the clolur of flame?</h3>

When a burner is properly adjusted the flame should have an outer violet oxidizing flame and an inner blue reducing flame. The temperature of blue colour is 15000 degree Celsius whereas the cool region outside the blue has 3000C temperature.

So we can conclude that When a bunsen burner is properly adjusted, the flame look like outer violet and inner blue colour.

Learn more about flame here: brainly.com/question/448102

8 0
2 years ago
A solution is 40.00% by volume benzene (C6H6) in carbon tetrachloride at 20°C. The vapor pressure of pure benzene at this temper
finlep [7]

Answer:

The total vapor pressure is 84.29 mmHg

Explanation:

Step 1:  Data given

Solution = 40.00 (v/v) % benzene in CCl4

Temperature = 20.00 °C

The vapor pressure of pure benzene at 20.00 °C = 74.61 mmHg

Density of benzene is 0.87865 g/cm3

The vapor pressure of pure carbon tetrachloride is 91.32 mmHg

We suppose the total volume = 100 mL

Step 2: Calculate volume benzene and CCl4

40 % benzene = 40 mL

60 % mL CCl4 = 60 mL

Step 3: Calculate mass benzene

Mass = density * volume

Mass of benzene = 40.00 mL *  0.87865 g/mL = 35.146 g

Step 4: Calculate moles of benzene

Moles = mass / molar mass

Number of moles of benzene  = 35.146 grams / 78 g/mol  = 0.45059 mol

Step 5: Calculate mass of CCl4

Mass of CCl4 = 60 mL * 1.5940 g/mL = 95.64 g

Step 6: Calculate moles CCl4

Number of moles of CCl4 = 95.64 grams / 154g/mol = 0.62104 mol

Step 7: Calculate total number of moles

Total number of moles = moles benzene + moles CCl4

0.45059 moles + 0.62104 moles = 1.07163 mol

Step 8: Calculate mole fraction benzene and CCl4

Mole fraction = moles benzene / total moles

Mole fraction of benzene = 0.45059 / 1.07163 = 0.4205

Mole fraction of CCl4 = 0.62104 / 1.07163 = 0.5795

Step 9: Calculate partial pressure

Partial pressure of benzene = 0.4205 * 74.61 = 31.37 mmHg

Partial pressure of CCl4      = 0.5795 * 91.32 = 52.92 mmHg

Total vapor pressure = 31.37 + 52.92 = 84.29 mmHg

The total vapor pressure is 84.29 mmHg

7 0
3 years ago
ASAP<br>what is an electron cloud ​
Bad White [126]

Explanation:

An electron cloud is the region of space that surrounds the nucleus of an atom under the nucleus of the negatively charged sub-atomic particles.

  • An atoms is made up of some particles.
  • The proton is positively charged and it is located in the nucleus of an atom.
  • The neutrons do not carry any charges and occupies the nucleus with protons.
  • Electrons are the negatively charged particles outside the nucleus.
  • The electron cloud is portion of an atom with greatest probability of finding an electron.

Learn more:

Electron cloud brainly.com/question/1832385

#learnwithBrainly

8 0
3 years ago
. How many grams of water would require 4400 joules
Alja [10]

Answer:

The specific heat of water is 4.18 J/g C.

Explanation:

q

=

m

C

s

Δ

T

Never forget that!

2200

=

m

⋅

4.18

J

g

⋅

°

C

⋅

66

°

C

∴

m

≈

8.0

g

5 0
3 years ago
A chemist measures the energy change ?H during the following reaction: 2HgO (s) ?2Hg (l) +O2 (g) =?H182.kJ Use the information t
Elan Coil [88]

Answer:

A. endothermic.

A. Yes, absorbed.

Explanation:

Let's consider the following thermochemical equation.

2 HgO(s) ⇒ 2 Hg(l) + O₂(g)  ΔH = 182 kJ

The enthalpy of the reaction is positive (ΔH > 0), which means that the reaction is endothermic.

182 kJ are absorbed when 2 moles of HgO react (molar mass 216.59 g/mol). The heat absorbed when 72.8 g of HgO react is:

72.8g.\frac{1mol}{216.59g} .\frac{182kJ}{2mol} =30.6kJ/mol

6 0
3 years ago
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