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OLEGan [10]
4 years ago
7

Give the correct thermochemical equations for a (cacl2+h2o) pack and (nh4no3+h2o) pack.

Chemistry
1 answer:
UkoKoshka [18]4 years ago
3 0

Explanation: A thermochemical equation is a balanced chemical equation which require an enthalpy change.

A balanced equation is the equation in which number of atoms on reactant side is same as the number of atoms on product side.

A thermochemical equation for CaCl_2+H_2O is:

CaCl_2+2H_2O\rightarrow Ca(OH)_2+2HCl+heat

Here, heat is released in the reaction hence, it is a type of exothermic reaction.

A thermochemical equation for NH_4NO_3+H_2O is:

NH_4NO_3+heat\overset{water}{\rightarrow} NH_4^++NO_3^-

Here, heat is absorbed in the reaction hence,it is a type of endothermic reaction.


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<u>Answer:</u> The concentration of SO_4^{2-} at equilibrium is 0.00608 M

<u>Explanation:</u>

As, sulfuric acid is a strong acid. So, its first dissociation will easily be done as the first dissociation constant is higher than the second dissociation constant.

In the second dissociation, the ions will remain in equilibrium.

We are given:

Concentration of sulfuric acid = 0.025 M

Equation for the first dissociation of sulfuric acid:

       H_2SO_4(aq.)\rightarrow H^+(aq.)+HSO_4^-(aq.)

            0.025          0.025       0.025

Equation for the second dissociation of sulfuric acid:

                    HSO_4^-(aq.)\rightarrow H^+(aq.)+SO_4^{2-}(aq.)

<u>Initial:</u>            0.025            0.025      

<u>At eqllm:</u>      0.025-x          0.025+x        x

The expression of second equilibrium constant equation follows:

Ka_2=\frac{[H^+][SO_4^{2-}]}{[HSO_4^-]}

We know that:

Ka_2\text{ for }H_2SO_4=0.01

Putting values in above equation, we get:

0.01=\frac{(0.025+x)\times x}{(0.025-x)}\\\\x=-0.0411,0.00608

Neglecting the negative value of 'x', because concentration cannot be negative.

So, equilibrium concentration of sulfate ion = x = 0.00608 M

Hence, the concentration of SO_4^{2-} at equilibrium is 0.00608 M

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