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masha68 [24]
3 years ago
7

HOW FAST CAN YOU ANSWER

Chemistry
1 answer:
Alex777 [14]3 years ago
5 0

Answer:

option "B" is correct (substance 2)

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What is the formula of sulfurous acid?<br> H2S<br> HSO4<br> H2SO4<br> H2SO3
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The correct answer is H2SO3 I took the assignment already


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Which of the following is a physical property of a substance?? A. Combustion B. Corrosion C. Tendency to tarnish D. Solubility
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A physical property does not change the substance. 

Solubility would be the answer since all of the rest are changing the substance. They all deal with bonds except solubility. 

Answer: D. Solubility

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What is the happens in electrolysis if the electrolyte solidifies?​
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Answer: For example, if electricity is passed through molten lead bromide, the lead bromide is broken down to form lead and bromine. This is what happens during electrolysis: Positively charged ions move to the negative electrode during electrolysis. ... Negatively charged ions move to the positive electrode during electrolysis.

Explanation:

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A chemist has synthesized two new dyes based on the molecular structure of plant-based dyes. The lowest energy absorption line f
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Answer:

1. The dye that absorbs at 530 nm

Explanation:

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The relationship between energy and wavelenght can be expressed by the formula E = hc/λ, this means that the <em>lower</em> the wavelenght, the <em>higher</em> the energy is. So the dye that absorbs at a lower wavelenght has a larger HOMO-LUMO gap.

7 0
3 years ago
A 2.00L flask was filled with 4.00 mol of HI at a certain temperature and given sufficient time to react. At equilibrium the con
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Answer:

The equilibrium concentration of I₂ is 0.400 M  and HI is 1.20 M, the Keq will be 0.112.

Explanation:

Based on the given information, the equilibrium reaction will be,  

2HI (g) ⇔ H₂ (g) + I₂ (g)

It is given that 4.00 mol of HI was filled in a flask of 2.00 L, thus, the concentration of HI will be,  

= 4.00 mol/2.00 L

= 2.00 mol/L

Based on the reaction, the initial concentration of 2HI is 2.00, H₂ is 0 and I₂ is O. The change in the concentration of 2HI is -x, H₂ is x and I₂ is x. The equilibrium concentration of 2HI will be 0.200-x, H₂ is x and I₂ is x.  

It is given that at equilibrium, the concentration of H₂ or x is 0.400 M.  

Now the equilibrium concentration of HI will be,  

= 2.00 -2x  

= 2.00 - 2 × 0.400

= 1.20 M

The equilibrium concentration of I₂ will be,  

I₂ = x  

= 0.400 M

The equilibrium constant (Keq) will be,  

Keq = [H₂] [I₂] / [HI]²

= (0.400) (0.400) / (1.20)²

= 0.112

Thus, the Keq of the reaction will be 0.112.  

5 0
3 years ago
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