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Margarita [4]
3 years ago
14

1 kg of aluminum requires 887 J (Joule) to raise its temperature by 1 K (Kelvin). The specific heat of aluminum is expressed as

(J/(kg*K)). For a 100 g aluminum bar, how much energy is needed to raise the temperature from -9oC to 1oC?
Physics
1 answer:
zavuch27 [327]3 years ago
3 0

Answer:

887 J

Explanation:

the specific heat of  a material is defined as the amount of heat energy required to raise the temperature of the substance by 1 K of mass 1 kg. So, the specific heat of the aluminium, c = 887 J/kg K

mass of aluminium, m = 100 g = 0.1 kg

T1 = - 9° C

T2 = 1° C

ΔT = 1 + 9 = 10° C

The amount of heat required

H = m x c x ΔT

H = 0.1 x 887 x 10 = 887 J

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3 years ago
2) Two ice skaters have masses m1 and m2 and are initially stationary. Their skates are identical. They push against one another
worty [1.4K]

Answer:

m_1 / m_2 = sqrt (1 / 2)

Explanation:

Given:

- Initial velocity of both skaters V_i = 0

- Velocity of skater 1 after push = V_1

- Velocity of skater  after push = V_2

- Distance traveled by skater 1 = s_1

- Distance traveled by skater 2 = s_2

- s_1 = 2*s_2

- Accelerations of both skaters to halt is equal

Find:

What is the ratio m1/m2 of their masses

Solution:

- Apply conservation of momentum for two skaters just before and after the push as follows:

                                              P_i = P_f

                                  0 = m_1*V_1 - m_2*V_2

- Evaluate:                 m_1 / m_2 = ( V_2 / V_1 )

- Apply Conservation of Energy on both skaters as follows:

- Skater 1:

                               0.5*m_1*V_1^2 = u_k*m_1*g*s_1

-Simplify:                      0.5*V_1^2 = u_k*g*(2*s_2)

- Skater 2:

                               0.5*m_2*V_2^2 = u_k*m_2*g*s_2

-Simplify:                      0.5*V_2^2 = u_k*g*s_2

- Divide the two energy equations for skaters:

                                    (V_1 / V_2)^2 = 2

                                    (V_2 / V_1)^2 = 1 / 2

- simplify:                     (V_2 / V_1) = sqrt (1 / 2)

-Hence from earlier momentum conservation results:

                                  m_1 / m_2 = ( V_2 / V_1 ) = sqrt (1 / 2)

6 0
3 years ago
A man runs 800m due north in 110 seconds followed by 400m due suoth in 90 seconds calculate his average speed and his average ve
andrey2020 [161]

Answer:

Average speed is  6m/s

Average velocity is 5.859m/s

Explanation:

Average speed, s = d/t

d is distant

t is time

speed north is 800m and 110s

speed due south is 400m and 90s  

Average speed = (800+400) / (110+90)

                          = 1200/200

                          =6m/s

Average velocity V = (v + u)/2

v = final velocity

u = initial velocity

V = (7.273 + 4.444)/2 = 11.717/2

V = 5.859m/s

6 0
3 years ago
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