Ask question

Ask question

All categories

3 years ago

14

1 kg of aluminum requires 887 J (Joule) to raise its temperature by 1 K (Kelvin). The specific heat of aluminum is expressed as

(J/(kg*K)). For a 100 g aluminum bar, how much energy is needed to raise the temperature from -9oC to 1oC?

1 answer:

zavuch27 [327]3 years ago

3 0

Answer:

887 J

Explanation:

the specific heat of a material is defined as the amount of heat energy required to raise the temperature of the substance by 1 K of mass 1 kg. So, the specific heat of the aluminium, c = 887 J/kg K

mass of aluminium, m = 100 g = 0.1 kg

T1 = - 9° C

T2 = 1° C

ΔT = 1 + 9 = 10° C

The amount of heat required

H = m x c x ΔT

H = 0.1 x 887 x 10 = 887 J

You might be interested in

Astronauts use a centrifuge to simulate the acceleration of a rocket launch. The centrifuge takes 40.0 s to speed up from rest t

Vinvika [58]

Answer

Time period T = 1.50 s

time t = 40 s

r = 6.2 m

a)

Angular speed ω = 2π/T

= $\dfrac{2\pi }{1.5}$

= 4.189 rad/s

Angular acceleration α = $\dfrac{\omega}{t}$

= $\dfrac{4.189}{40}$

= 0.105 rad/s²

Tangential acceleration a = r α = 6.2 x 0.105 = 0.651 m/s²

b)The maximum speed.

v = 2πr/T

= $\dfrac{2\pi \times 6.2}{1.5}$

= 25.97 m/s

So centripetal acceleration.

a = $\dfrac{v^2}{r}$

= $\dfrac{25.97^2}{6.2}$

= 108.781 m/s^2

= 11.1 g

in combination with the gravitation acceleration.

$a_{total} = \sqrt{(11.1g)^2+g^2}$

$a_{total}= 11.145 g$

6 0

4 years ago

Which substances are inorganic? Check all that apply.

bezimeni [28]

The major characteristic an organic compound has which an inorganic

compound doesn't have is the presence of carbon atoms in the molecule.

This helps us to differentiate the compounds into their respective divisions.

Inorganic compounds

K2CO3

Fe3O4

Organic compounds

C6H12O6

C4H10

C27H46O

We can observe that inorganic compounds lack carbon atoms which makes

the answer valid.

Read more about inorganic compounds on brainly.com/question/2169750

3 0

3 years ago

Which statement(s) correctly compare the masses of protons, neutrons, and electrons?

Ostrovityanka [42]

Electron<span>. the central part of an atom containing </span>protons<span> and </span>neutrons<span> ... which of the following is necessary to calculate the atomic </span>mass<span> of an element? ... which of the </span>statements correctly compares<span>the relative size of an ion to its neutral atom?</span>

3 0

3 years ago

1) A thin ring made of uniformly charged insulating material has total charge Q and radius R. The ring is positioned along the x

allochka39001 [22]

Answer:

(A) considering the charge "q" evenly distributed, applying the technique of charge integration for finite charges, you obtain the expression for the potential along any point in the Z-axis:

$V(z)=\frac{Q}{4\pi (\epsilon_{0}) \sqrt{R^{2} +z^{2}} }$

With $(\epsilon_{0})$ been the vacuum permittivity

(B) The expression for the magnitude of the E(z) electric field along the Z-axis is:

$E(z)=\frac{QZ}{4\pi (\epsilon_{0}) (R^{2} +z^{2})^{\frac{3}{2} } }$

Explanation:

(A) Considering a uniform linear density $λ_{0}$ on the ring, then:

$dQ=\lambda dl$ (1)⇒ $Q=\lambda_{0} 2\pi R$ (2)⇒ $\lambda_{0}=\frac{Q}{2\pi R}$ (3)

Applying the technique of charge integration for finite charges:

$V(z)= 4\pi (ε_{0})\int\limits^a_b {\frac{1}{ r' }} \, dQ$ (4)

Been r' the distance between the charge and the observation point and a, b limits of integration of the charge. In this case a=2π and b=0.

Using cylindrical coordinates, the distance between a point of the Z-axis and a point of a ring with R radius is:

$r'=\sqrt{R^{2} +Z^{2}}$ (5)

Using the expressions (1),(4) and (5) you obtain:

$V(z)= 4\pi (\epsilon_{0})\int\limits^a_b {\frac{\lambda_{0}R}{ \sqrt{R^{2} +Z^{2}} }} \, d\phi$

Integrating results:

$V(z)=\frac{Q}{4\pi (\epsilon_{0}) \sqrt{R^{2} +z^{2}} }$ (S_a)

(B) For the expression of the magnitude of the field E(z), is important to remember:

$|E| =-\nabla V$ (6)

But in this case you only work in the z variable, soo the expression (6) can be rewritten as:

$|E| =-\frac{dV(z)}{dz}$ (7)

Using expression (7) and (S_a), you get the expression of the magnitude of the field E(z):

$E(z)=\frac{QZ}{4\pi (\epsilon_{0}) (R^{2} +z^{2})^{\frac{3}{2} } }$ (S_b)

4 0

3 years ago

You take your pulse and observe 80 heartbeats in a minute. What is the period of your heartbeat? What is the frequency of your h

Mama L [17]

Answer:

120 beats per minute.

Explanation:

6 0

3 years ago

Read 2 more answers