An ___ wave carries energy through matter

Let's analyze this problem, the rocket is on a car that moves horizontally, so the rocket also has the same speed as the car; The initial horizontal rocket speed is (v₀ₓ = 3.0 m/s).

On the other hand, when starting the engines we have a vertical force, which creates an acceleration in the vertical axis, let's use Newton's second law to find this vertical acceleration

F -W = m a

a = (F-mg) / m

a = F/m -g

a = 7.0/0.500 - 9.8

a = 4.2 m/s²

We see that we have a positive acceleration and that is what we are going to use in the parabolic motion equations

Let's look for the time it takes for the rocket to reach the height (y = 15m) of the hoop, when the rocket fires its initial vertical velocity is zero (I'm going = 0)

y = $v_{oy}$ t + ½ a t²

y = 0 + ½ a t²

t = √ 2y/a

t = √( 2 15 / 4.2)

t = 2.67 s

This time is also the one that takes in the horizontal movement, let's calculate how far it travels

x = v₀ₓ t

x = 3 2.67

x = 8 m

The rocket has to be launched 8 m from the hoop

8 0

3 years ago

How many newtons of force will 2 pieces of paper have if one has a charge of .2 Coilombs and the other has a charge of .3 Coulom

sdas [7]

1) The electrostatic force between the two pieces of paper is $2.16\cdot 10^{13} N$

2)

If the charges of the two pieces of paper are both + or both -, they repel each other
If the charges of one piece of paper is positive and the other one is negative, they attract each other

Explanation:

1)

The electrostatic force between two charged objects is given by Coulomb's law:

$F=k\frac{q_1 q_2}{r^2}$

where:

$k=8.99\cdot 10^9 Nm^{-2}C^{-2}$ is the Coulomb's constant

$q_1, q_2$ are the two charges

r is the separation between the two charges

In this problem, we have the following situation:

$q_1 = 0.2 C$ is the charge on the first piece of paper

$q_2 = 0.3 C$ is the charge on the second piece of paper

$r=0.005 m$ is their separation

Substituting into the equation, we find the magnitude of the electrostatic force between them:

$F=k\frac{q_1 q_2}{r^2}=(8.99\cdot 10^9) \frac{(0.2)(0.3)}{(0.005)^2}=2.16\cdot 10^{13} N$

2)

The electrostatic force can be either attractive of repulsive, depending on the relative sign of the charges of the objects involved.

In particular, we have:

If the two charges have same sign (both positive or both negative), the force between them is repulsive
If the two charges have opposite sign (one positive and one negative), the force between them is attractive

Therefore, in this case:

If the charges of the two pieces of paper are both + or both -, they repel each other
If the charges of one piece of paper is positive and the other one is negative, they attract each other

Learn more about electric force:

brainly.com/question/8960054

brainly.com/question/4273177

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7 0

4 years ago