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velikii [3]
3 years ago
11

Hey can anyone help me with my physics exam​

Physics
2 answers:
Ierofanga [76]3 years ago
7 0
25 is the correct answer
Alona [7]3 years ago
5 0

Answer:

25 is the correct answer

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A dog is 60 m away while moving at a constant velocity of 10 m/s towards you. Where is the dog after 4 seconds?
joja [24]
The dog would be 20 m away from you.
4 0
3 years ago
Read 2 more answers
What is the total distance that the object traveled?
Natasha_Volkova [10]

Answer:

for what?

Explanation:

d=S x T

or

d=vt+1/2at2

srry if wrong but

hope this helps

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8 0
3 years ago
Is the velocity used to calculate reynolds number, average velocity?
aliina [53]
Yes/..................................................
4 0
3 years ago
A .5kg football is thrown with a velocity of 15m/s to the right. A stationary receiver catch the bail and bring it to rest in 0.
storchak [24]
<h3>Answer:</h3>

375 N

<h3>Explanation:</h3>

Topic tested: Newton's Law of motion

The question is testing on the application of Newton's second Law of motion.

We are given;

  • Mass of the football = 5 Kg
  • Initial velocity of the football, Vf = 15 m/s
  • Time taken to bring the ball to rest = 0.2 s
  • Final velocity, Vo = 0 m/s ( since the ball went to rest)

We are required to determine the force exerted to bring it to rest.

  • According to the Newton's second law of motion the resultant force and rate of change in momentum are directly proportion.
  • Therefore;

F=\frac{(MVf-MVo)}{t}

Thus;

F=\frac{(5kg.5m/s)-(5kg.0m/s)}{0.2s}

F=375Newtons

Force = 375 N

Hence, the force exerted on the ball by the receiver was 375 N

5 0
4 years ago
You have 0.5 l of air at a pressure of 203 kpa and -70°c in a rigid, sealed contaainer. what is the absolute tempertaure of the
ANTONII [103]
From the information given and if the question is complete then;
Absolute temperature is the temperature in Kelvin
To convert degree Celsius to kelvin we normally add 273
that is Kelvin = deg Celsius + 273
Thus since we have been given that the air was at -70 degrees celcius;
then; - 70° C  + 273 = 203 K
 Therefore; the absolute temperature is 203 K 

5 0
3 years ago
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