Question

How many moles of calcium chloride are theoretically produced for the following reaction given we have 2.6 moles of HCl and 1.4 moles of Ca(OH)2? Reaction: 2HCl + Ca(OH)2 → 2H2O + CaCl2

Answer 1

Answer : The number of moles of calcium chloride theoretically produced are, 1.3 moles.

Explanation : Given,

Moles of HCl = 2.6 moles

Moles of $Ca(OH)_2$ = 1.4 moles

Now we have to calculate the limiting and excess reagent.

The given balanced chemical reaction is:

$2HCl+Ca(OH)_2\rightarrow 2H_2O+CaCl_2$

From the balanced reaction we conclude that

As, 2 mole of $HCl$ react with 1 mole of $Ca(OH)_2$

So, 2.6 moles of $HCl$ react with $\frac{2.6}{2}=1.3$ moles of $Ca(OH)_2$

From this we conclude that, $Ca(OH)_2$ is an excess reagent because the given moles are greater than the required moles and $HCl$ is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of $CaCl_2$

From the reaction, we conclude that

As, 2 mole of $HCl$ react to give 1 mole of $CaCl_2$

So, 2.6 moles of $HCl$ react to give $\frac{2.6}{2}=1.3$moles of $CaCl_2$

Therefore, the number of moles of calcium chloride theoretically produced are, 1.3 moles.