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3 years ago

R is the midpoint of AM. If RA = x2 - 16x and MR = 80, find x.

Mathematics

1 answer:

sergij07 [2.7K]3 years ago

3 0

Answer:

x = - 4 or x = 20

Step-by-step explanation:

Given R is the midpoint of AM, then

RA = MR , substitute values

x² - 16x = 80 ( subtract 80 from both sides )

x² - 16x - 80 = 0 ← in standard form

(x - 20)(x + 4) = 0 ← in factored form

Equate each factor to zero and solve for x

x - 20 = 0 ⇒ x = 20

x + 4 = 0 ⇒ x = - 4

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Suppose a student's score on a standardize test to be a continuous random variable whose distribution follows the Normal curve.

blsea [12.9K]

Answer:

a) Percentage of students scored below 300 is 1.79%.

b) Score puts someone in the 90th percentile is 638.

Step-by-step explanation:

Given : Suppose a student's score on a standardize test to be a continuous random variable whose distribution follows the Normal curve.

(a) If the average test score is 510 with a standard deviation of 100 points.

To find : What percentage of students scored below 300 ?

Solution :

Mean $\mu=510$ ,

Standard deviation $\sigma=100$

Sample mean $x=300$

Percentage of students scored below 300 is given by,

$P(Z\leq \frac{x-\mu}{\sigma})\times 100$

$=P(Z\leq \frac{300-510}{100})\times 100$

$=P(Z\leq \frac{-210}{100})\times 100$

$=P(Z\leq-2.1)\times 100$

$=0.0179\times 100$

$=1.79\%$

Percentage of students scored below 300 is 1.79%.

(b) What score puts someone in the 90th percentile?

90th percentile is such that,

$P(x\leq t)=0.90$

Now, $P(\frac{x-\mu}{\sigma} < \frac{t-\mu}{\sigma})=0.90$

$P(Z< \frac{t-\mu}{\sigma})=0.90$

$\frac{t-\mu}{\sigma}=1.28$

$\frac{t-510}{100}=1.28$

$t-510=128$

$t=128+510$

$t=638$

Score puts someone in the 90th percentile is 638.

5 0

3 years ago

Can someone please help me

Yuri [45]

Answer:

the answer is d

Step-by-step explanation:

8 0

3 years ago

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20x^3+8x^2-30x-12 Rewrite the expression as the product of two binomials.

weqwewe [10]

Answer:

see below

Step-by-step explanation:

20x^3+8x^2-30x-12

Factor out the greatest common factor 2

2 (10x^3+4x^2-15x-6)

Then factor by grouping

2 ( 10x^3+4x^2 -15x-6)

Factor out 2 x^2 from the first group and -3 from the second group

2 ( 2x^2( 5x+2) -3( 5x+2))

Factor out ( 5x+2)

2 ( 5x+2) (2x^2-3)

The 2 can go in either term to get binomials

( 10x +4) (2x^2-3)

or ( 5x+2) ( 4x^2 -6)

3 0

3 years ago

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The standard form of -36/-216

GrogVix [38]

Answer:

$\frac{1}{6}$

Step-by-step explanation:

$\frac{-36}{-216} \\=\frac{36}{216} \\=\frac{1}{6}$

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3 years ago

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The nth term of a sequence is 2N - six

dolphi86 [110]

Answer:

ok nice to know

Step-by-step explanation:

that wasnt even a ????

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2 years ago